Testing a Claim about a Population Proportion Answers

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5

According to a soccer coach, 75% of soccer players have had at least one sprained ankle. An athletic trainer would like to investigate this claim. To do so, the trainer selects a random sample of 125 college soccer players from across the country and finds that 99 of them have had at least one sprained ankle. The trainer would like to know if the data provide convincing evidence that the true proportion of college soccer players who have had at least one sprained ankle is greater than 75%. The computer output gives the results of a z-test for one proportion.Test and CI for One ProportionTest of p = 0.75 vs p > 0.75Sample1X99N125Sample p0.79295% CI(0.72085, 0.86315)Z-Value1.084P-value0.1391

A
There is convincing evidence that college soccer players will have at least one sprained ankle at least 75% of the time.
B
There is not convincing evidence that college soccer players will have at least one sprained ankle more than 75% of the time.
C
There is convincing evidence that the true proportion of college soccer players who have had at least one sprained ankle is greater than 75%.
D
There is not convincing evidence that the true proportion of college soccer players who have had at least one sprained ankle is greater than 75%.
6

An emergency fund is defined as a savings account that has a balance equal to at least two months’ living expenses. An article in a financial magazine claims that 80% of American adults do not have an emergency fund. To investigate this claim, a financial advisor selects a random sample of 150 Americans and finds that 112 do not have an emergency fund. The financial advisor would like to know if the data provide convincing evidence that the true proportion of American adults who do not have an emergency fund is less than 80%. The financial advisor tests the hypotheses H0: p = 0.80 versus Ha: p < 0.80, where p = the true proportion of all American adults that do not have an emergency fund. The conditions for inference are met. The standardized test statistic is z = –1.62 and the P-value is 0.0526. What conclusion should the financial advisor make using the α = 0.05 significance level?

A
Because the P-value is greater than α = 0.05, there is convincing evidence that the true proportion of American adults who do not have an emergency fund is less than 80%.
B
Because the P-value is greater than α = 0.05, there is convincing evidence that the true proportion of American adults who do not have an emergency fund is greater than 80%.
C
Because the P-value is greater than α = 0.05, there is not convincing evidence that the true proportion of American adults who do not have an emergency fund is less than 80%.
D
Because the P-value is greater than α = 0.05, there is not convincing evidence that the true proportion of American adults who do not have an emergency fund is greater than 80%.
7

An emergency fund is defined as a savings account that has a balance equal to at least two months’ living expenses. An article in a financial magazine claims that 80% of American adults do not have an emergency fund. To investigate this claim, a financial advisor selects a random sample of 150 Americans and finds that 112 do not have an emergency fund. The financial advisor would like to know if the data provide convincing evidence that the true proportion of American adults who do not have an emergency fund is less than 80%.

A
The financial advisor could use a sample size that is larger than 150 and use a significance level that is larger than α = 0.05.
B
The financial advisor could use a sample size that is larger than 150 and use a significance level that is smaller than α = 0.05.
C
The financial advisor could use a sample size that is smaller than 150 and use a significance level that is larger than α = 0.05.
D
The financial advisor could use a sample size that is smaller than 150 and use a significance level that is smaller than α = 0.05.
8

An emergency fund is defined as a savings account that has a balance equal to at least two months’ living expenses. An article in a financial magazine claims that 80% of American adults do not have an emergency fund. To investigate this claim, a financial advisor selects a random sample of 150 American adults and finds that 112 do not have an emergency fund. The financial advisor would like to know if the data provide convincing evidence that the true proportion of Americans who do not have an emergency fund is less than 80%. What are the appropriate hypotheses for this test?

A
H0: p = 0.80 versus Ha: p < 0.80, where p = the true proportion of all American adults who do not have an emergency fund.
B
H0: p < 0.80 versus Ha: p = 0.80, where p = the true proportion of all American adults who do not have an emergency fund.
C
H0: p = 0.80 versus Ha: p < 0.80, where p = the proportion of American adults in the sample who do not have an emergency fund.
D
H0: p < 0.80 versus Ha: p = 0.80, where p = the proportion of American adults in the sample who do not have an emergency fund.

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