AnswersPrecalculusThe General Equation of Conic Sections

The General Equation of Conic Sections Answers

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Mariah converted the following equation into standard form.25x2 + 25y2 – 200x + 100y + 4 = 025x2 – 200x + 25y2 + 100y = –425(x2 – 8x) + 25(y2 + 4y) = –425(x2 – 8x + 16) + 25(y2 + 4y + 4) = –4 + 16 + 425(x – 4)2 + 25(y + 2)2 = 16

A
Mariah did not make an error.
B
Mariah listed the center incorrectly. The center should be (–4, 2).
C
Mariah should have added 400 and 100 to the right side of the equation in step 4
D
Mariah factored incorrectly in step 5. She should have factored to (x – 8)2 and (y + 4)2.
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Graph .

Question illustration
A
On a coordinate plane, an Ellipse has center point (4, 0) and goes through (4, 2), (7, 0), (4, negative 2), and (1, 0).
Option A
B
On a coordinate plane, an Ellipse has center point (negative 4, 0) and goes through (negative 1, 0), (negative 4, 2), (negative 7, 0) and (negative 4, negative 2).
Option B
C
On a coordinate plane, an Ellipse has center (4, 0) and goes through (6, 0), (4, negative 3), (2, 0) and (4, 3).
Option C
D
On a coordinate plane, an Ellipse has center (negative 4, 0) and goes through (negative 2, 0), (negative 4, 3), (negative 6, 0) and (negative 4, negative 3).
Option D
3

Graph .

Question illustration
A
On a coordinate plane, one part of a conic graph goes through (negative 1, 1), has a vertex at (0, negative 3), and goes through (negative 1, negative 7).
Option A
B
On a coordinate plane, one part of a conic graph goes through (negative 11, 8), has a vertex at (negative 10, 3), and goes through (negative 11, negative 1). The other part goes through (1, 7) has a vertex at (0, 3), and goes through (1, negative 1).
Option B
C
On a coordinate plane, an Ellipse has center (5, negative 3) and goes through (10, negative 3), (5, negative 9), (0, negative 3), and (5, 3).
Option C
D
On a coordinate plane, an Ellipse has center (5, 3) and goes through (negative 5, 9), (0, 3), (5, negative 3), and (negative 10, 3).
Option D
4

Which equation represents a parabola?

A
4x2 – 2x + 3y2 – y + 1 = 0
B
x2 + x – 2y2 – 4y + 2 = 0
C
–3x + 4y2 – 2y + 6 = 0
D
2x2 + y2 – 4y + 6 = 0

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