1
QuizMultiple Choice
The Nucleus
Question 1 • TX-Chemistry B
The following equations are half reactions and reduction potentials. Li+ (aq) + e– Li(s) has a reduction potential of –3.04 V F2(g) + 2e– 2F–(aq) has a reduction potential of +2.87 VNow consider lithium (LI+) and fluoride (F2) as oxidizing agents. How do these compare as oxidizing agents?
Answer
A
Lithium is a stronger oxidizing agent than fluoride.B
Fluoride is a stronger oxidizing agent than lithium.C
Fluoride and lithium have the same oxidizing strength.D
Reduction potential and oxidizing/reducing strength are unrelated.