Yuri thinks that is a root of the following function.q(x) = 6x3 + 19x2 – 15x – 28Explain to Yuri why cannot be a root.
According to the Rational Root Theorem, potential rational roots must be in the form p/q, where p is a factor of the constant term (28) and q is a factor of the leading coefficient (6). Since 3 is not a factor of 28 and 4 is not a factor of 6, 3/4 cannot be a rational root. Additionally, substituting 3/4 into the function for x does not result in 0, and dividing the polynomial by (x 3/4) would result in a nonzero remainder, confirming that 3/4 is not a root.
Use synthetic division to test one potential root. Enter the numbers that complete the division problem.
p(−2) = [___]
0
No, this polynomial has complex roots.No, this polynomial has irrational roots.No, this polynomial has irrational and complex roots.Yes.
Which of the numbers below are some potential roots of p(x) = x3 + 6x2 − 7x − 60 according to the rational root theorem?
Which of the number(s) below are potential roots of the function?q(x) = 6x3 + 19x2 – 15x – 28




Question text not available
⇒ -5
answer
Did you include the following in your response?



No, this polynomial has complex roots.No, this polynomial has irrational roots.No, this polynomial has irrational and complex roots.Yes.
Question text not available
-16
Question text not available
⇒ 1
answer
–16✔ –202
⇒ -5
answer
⇒ -12
answer
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