To obtain the graph of y = x2 - 6, shift the graph of y = x2 up✔ downleftright
).
Factor the perfect-square trinomial in y = (x2 + 2x + 1) − 1− 1.y = (x + [___])2 − 1 −1
Write in vertex form. y = 8(x + ⇒ 2)2 + ⇒ -15
).
Simplify.y = (x + 1)2 − [___]
y = 8(x + [___])2 + [___]
⇒ -5
-5
⇒ 3
3
units.
8
units.
6
The vertex of the graph of y = (x - 1)2 - 5 is The vertex of the graph of y = -4(x + 3)2 + 2 is
).
-5
The vertex of the graph of y = (x - 1)2 - 5 is The vertex of the graph of y = -4(x + 3)2 + 2 is
).
2
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Enter the values of h and k so that y = x2 + 6x + 10 is in vertex form.
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