AnswersLAUSD-Pre-Calculus B PrescriptiveUnit Test

Transformations of Quadratic Functions Answers

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Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)?Distance formula:

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A
(x – 4)2 + y2 = 100
B
(x – 4)2 + y2 = 10
C
x2 + (y – 4)² = 10
D
x2 + (y – 4)² = 100
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On a coordinate plane, a circle has a center at (1, negative 2) and a radius of 4 units.

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A
(x – 1)2 + (y + 1)2 = 16
B
(x – 1)2 + (y + 1)2 = 4
C
(x + 1)2 + (y –1)2 = 4
D
(x + 1)2 + (y – 1)2 = 16
3

Which point is on the circle centered at the origin with a radius of 5 units?Distance formula:

Question illustration
A
(2, )
Option A
B
(2, )
Option B
C
(2, 1)
D
(2, 3)
4

Which explains how to find the radius of a circle whose equation is in the form x2 + y2 = z?

A
The radius is the constant term, z.
B
The radius is the constant term, z, divided by 2.
C
The radius is the square root of the constant term, z.
D
The radius is the square of the constant term, z.
5

What is the center of a circle represented by the equation (x+9)2+(y−6)2=102?

A
(−9,6)
B
(−6,9)
C
(6,−9)
D
(9,−6)
6

Which equation represents a circle with a center at (–4, 9) and a diameter of 10 units?

A
(x – 9)2 + (y + 4)2 = 25
B
(x + 4)2 + (y – 9)2 = 25
C
(x – 9)2 + (y + 4)2 = 100
D
(x + 4)2 + (y – 9)2 = 100
7

Distance formula:

Question illustration
A
Yes, the distance from (–2, 4) to (1, ) is 4 units.
Option A
B
Yes, the distance from (–2, 0) to (1, ) is 4 units.
Option B
C
No, the distance from (–2, 0) to (1, ) is not 4 units.
Option C
D
No, the distance from (–2, 4) to (1, ) is not 4 units.
Option D
8

What is the radius of a circle whose equation is x2+y2+8x−6y+21=0?

A
2 units
B
3 units
C
4 units
D
5 units
9

Which equation represents a circle with a center at (–3, –5) and a radius of 6 units?

A
(x – 3)2 + (y – 5)2 = 6
B
(x – 3)2 + (y – 5)2 = 36
C
(x + 3)2 + (y + 5)2 = 6
D
(x + 3)2 + (y + 5)2 = 36
10

Which equation represents a circle that contains the point (–5, –3) and has a center at (–2, 1)? Distance formula:

Question illustration
A
(x – 1)2 + (y + 2)2 = 25
B
(x + 2)2 + (y – 1)2 = 5
C
(x + 2)2 + (y – 1)2 = 25
D
(x – 1)2 + (y + 2)2 = 5

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