AnswersBISD TX-Geometry A-CRTriangle Congruence: SAS

Triangle Congruence: SAS Answers

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Triangles RQS and NTV have the following characteristics:• Right angles at ∠Q and ∠T • RQ ≅ NTCan it be concluded that ΔRQS ≅ ΔNTV by SAS? Why or why not?

A
Yes, one set of corresponding sides and one corresponding angle are congruent.
B
Yes, they are both right triangles.
C
No, it is necessary to know that another set of corresponding sides is congruent.
D
No, it is not possible for the triangles to be congruent.
2
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Which of these triangle pairs can be mapped to each other using a single reflection?

Question illustration
A
Triangles F E G and F G L are congruent. Triangle F E G is reflected across line F G to form triangle F G L.
Option A
B
Triangles F E G and G L M are congruent. Triangle E F G is rotated about point G to form triangle G L M.
Option B
C
Triangles F E G and L M N are congruent. Triangle F E G is shifted down and to the right to form triangle L M N.
Option C
D
Triangles L M N and E F G are congruent. Triangle F E G is reflected across a line to form triangle L M N. Triangle L M N is also slightly higher and to the right of triangle E F G.
Option D
3

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K.

Question illustration
A
Translate H to L and rotate about H until HK lies on the line containing LM.
B
Translate K to M and rotate about K until HK lies on the line containing LM.
C
Translate K to N and rotate about K until HK lies on the line containing LN.
D
Translate H to N and rotate about H until HK lies on the line containing LN.
4

Triangles J K L and M N R are shown.

Question illustration
∠
∠J ≅ ∠M
∠
∠L ≅ ∠R
∠
∠K ≅ ∠N
∠
∠R ≅ ∠K
5

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K.

Question illustration
a
a reflection across the line containing HK
a
a rotation about point H
a
a reflection across the line containing HJ
a
a rotation about point K
6

Triangles A Q R and A K P share point A. Triangle A Q R is rotated up and to the right for form triangle A Q R.

Question illustration
a
a rotation about point A
a
a reflection across the line containing AR
a
a reflection across the line containing AQ
a
a rotation about point R
7

How can ΔWXY be mapped to ΔMNQ?

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
9

Parallelogram V W Z X is shown. Point Y is at the bottom center of the shape. Lines are drawn from points V to X through point Y and from points W to Z through point Y. 4 triangles are formed by the lines.

Question illustration
A
Yes, along with the given information, ZX ≅ ZX by the reflexive property.
B
Yes, the triangles are both obtuse.
C
No, the sides of the triangles intersect.
D
No, there is not enough information given.
11

Triangles A B C and X Y Z is congruent. Triangle X Y Z is slightly higher and to the right of triangle A B C. Triangle A B C is reflected across a line to form triangle X Y Z.

Question illustration
a
a reflection across the line containing AB
a
a reflection across the line containing AC
a
a rotation about point A
a
a rotation about point B
12

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K.

Question illustration
A
Translate H to L and rotate about H until HK lies on the line containing LM.
B
Translate K to M and rotate about K until HK lies on the line containing LM.
C
Translate K to N and rotate about K until HK lies on the line containing LN.
D
Translate H to N and rotate about H until HK lies on the line containing LN.
13

Which of these triangle pairs can be mapped to each other using both a translation and a reflection across the line containing AB?

A
Triangles X Y Z and A B C are congruent. Triangle X Y Z is reflected across a line to form triangle A B C. It is also slightly higher than triangle A B C.
Option A
B
Triangles A B C and A Y C are congruent and share common side A C. Triangle A B C is reflected across line A C to form triangle A Y C.
Option B
C
Triangles A B C and X Y Z are congruent. Triangle X Y Z is slightly higher and to the right of triangle A B C.
Option C
D
Triangles A B C and X Y Z are congruent. Triangle A B C is rotated to the right to form triangles X Y Z. Triangle X Y Z is also higher and to the right of triangle A B C.
Option D
14

Triangles A B C and X Y Z is congruent. Triangle X Y Z is slightly higher and to the right of triangle A B C. Triangle A B C is reflected across a line to form triangle X Y Z.

Question illustration
A
a reflection across the line containing AB
B
a reflection across the line containing AC
C
a rotation about point A
D
a rotation about point B
15

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K.

Question illustration
A
a reflection across the line containing HK
B
a rotation about point H
C
a reflection across the line containing HJ
D
a rotation about point K
16

Which of these triangle pairs can be mapped to each other using a single translation?

A
Triangles C E D and C N P are congruent. Triangle C E D is rotated about point C and then reflected across a line to form triangle C N P.
Option A
B
Triangles C N E and C E D are congruent. Triangle C N E is reflected across a line and then rotated slightly to form triangle C E D.
Option B
C
Triangles C E D and M D P are congruent. Triangle M D P is rotated and shifted up to form triangle C E D.
Option C
D
Triangles C E D and M P N are congruent. Triangle C E D is shifted to the right to form triangle M P N.
Option D
17

both

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
18

The proof that ΔACB ≅ ΔECD is shown.Given: AE and DB bisect each other at C.Prove: ΔACB ≅ ΔECD

Question illustration
A
∠BAC ≅ ∠DEC
B
∠ACD ≅ ∠ECB
C
∠ACB ≅ ∠ECD
D
∠BCA ≅ ∠DCA
19

both

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
20

The proof that ΔEFG ≅ ΔJHG is shown.Given: G is the midpoint of HF, EF ∥ HJ, and EF ≅ HJ.Prove: ΔEFG ≅ ΔJHG Statement Reason1.G is the midpoint of HF1.given2.FG ≅ HG2.def. of midpoint3.EF ∥ HJ3.given4.?4.alt. int. angles are congruent5.EF ≅ HJ5. given6.ΔEFG ≅ ΔJHG6.SAS

Question illustration
A
∠FEG ≅ ∠HJG
B
∠GFE ≅ ∠GHJ
C
∠EGF ≅ ∠JGH
D
∠GEF ≅ ∠JHG

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