Triangle Congruence: SAS Answers

Triangles A Q R and A K P share point A. Triangle A Q R is rotated up and to the right for form triangle A Q R.

Which of these triangle pairs can be mapped to each other using a single translation?

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K.

The proof that ΔEFG ≅ ΔJHG is shown.Given: G is the midpoint of HF, EF ∥ HJ, and EF ≅ HJ.Prove: ΔEFG ≅ ΔJHG Statement Reason1.G is the midpoint of HF1.given2.FG ≅ HG2.def. of midpoint3.EF ∥ HJ3.given4.?4.alt. int. angles are congruent5.EF ≅ HJ5. given6.ΔEFG ≅ ΔJHG6.SAS

Triangles RQS and NTV have the following characteristics:• Right angles at ∠Q and ∠T • RQ ≅ NTCan it be concluded that ΔRQS ≅ ΔNTV by SAS? Why or why not?

Triangles A B C and X Y Z is congruent. Triangle X Y Z is slightly higher and to the right of triangle A B C. Triangle A B C is reflected across a line to form triangle X Y Z.

How can ΔWXY be mapped to ΔMNQ?

If bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three options.

The proof that ΔACB ≅ ΔECD is shown.Given: AE and DB bisect each other at C.Prove: ΔACB ≅ ΔECD

Parallelogram V W Z X is shown. Point Y is at the bottom center of the shape. Lines are drawn from points V to X through point Y and from points W to Z through point Y. 4 triangles are formed by the lines.