Question 21 • CMS 2026-2027 Foundations of Math 3 INITIAL CREDIT
A reflection preserves lengths and angles, and a dilation by a factor of 2/3 multiplies every side length by 2/3. Thus DE = (2/3)AB, so 3DE = 2AB, making A true. The transformation matches A with D and B with E, so corresponding angles B and E are congruent, making D true. A reflection followed by a dilation preserves angle measures and keeps side lengths in the same ratio, so the triangles are similar, making E true.
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