What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12?

Distribute −3: −18 + 6x ≥ 4x + 12. Subtract 4x from both sides and add 18 to both sides to get 2x ≥ 30, so x ≥ 15. The interval is [15, ∞), which is choice D.

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