AnswersAZ-Common Core Algebra II BLinear Growth vs. Exponential Growth

Linear Growth vs. Exponential Growth — Unit test Answers

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Tanisha is graphing the function f(x) = 25()x. She begins by plotting the point (1, 15). Which could be the next point she plots on the graph?

Question illustration
A
(2, 9)
B
(2, –10)
C
(2, 14)
Option C
D
(2, 5)
24

An exponential growth function has an asymptote of y = –3. Which might have occurred in the original function to permit the range to include negative numbers?

A
A whole number constant could have been added to the exponential expression.
B
A whole number constant could have been subtracted from the exponential expression.
C
A whole number constant could have been added to the exponent.
D
A whole number constant could have been subtracted from the exponent.
26

Which linear function represents the line given by the point-slope equation y + 7 = –(x + 6)?

Question illustration
A
f(x) = –x – 11
Option A
B
f(x) = –x – 1
Option B
C
f(x) = –x + 3
Option C
D
f(x) = –x + 13
Option D
27

Which is the graph of f(x) = 2(3)x?

A
Option
B
Option
C
Option
D
Option
28

The depth of snow after n hours of a snowstorm is represented by the function f(n + 1) = f(n) + 0.8 where f(0) = 2.5. Which statement describes the sequence of numbers generated by the function?

A
The depth of snow was 0.8 inches when the storm began, and 2.5 inches after the first hour of the storm.
B
The depth of snow was 1.7 inches when the storm began, and 0.8 inches of snow fell each hour.
C
The depth of snow was 2.5 inches when the storm began, and increased by 0.8 inches each hour.
D
The depth of snow was 3.3 inches when the storm began, and 2.5 inches of snow fell in 1 hour.
29

Pherris is graphing the function f(x) = 2(3)x. He begins with the point (1, 6). Which could be the next point on his graph?

A
(2, 12)
B
(2, 18)
C
(2, 7)
D
(3, 7)
30

Karl has stamps in his desk drawer. The possible combinations of stamps are shown below.

Question illustration
A
The total number of stamps is 25.
B
The total value of the stamps is $18.75.
C
The total number of stamps is 35.
D
The total value of the stamps is $19.15.
31

Which type of function is represented by the table of values below?xy14216364425651,024

A
exponential
B
linear
C
quadratic
D
square root
32

Timmy writes the equation f(x) = x – 1. He then doubles both of the terms on the right side to create the equation g(x) = x – 2. How does the graph of g(x) compare to the graph of f(x)?

Question illustration
A
The line of g(x) is steeper and has a higher y-intercept.
B
The line of g(x) is less steep and has a lower y-intercept.
C
The line of g(x) is steeper and has a lower y-intercept.
D
The line of g(x) is less steep and has a higher y-intercept.
33

A line that passes through the points (–4, 10) and (–1, 5) can be represented by the equation y = (x – 2). Which equations also represent this line? Select three options.

Question illustration
A
y = x – 2
Option A
B
y = x +
Option B
C
3y = –5x + 10
D
3x + 15y = 30
E
5x + 3y = 10
34

The graph below shows the total cost for lunch, c, when Will and his friends buy a large salad to share and several slices of pizza, p.

Question illustration
A
$1.50
B
$2.00
C
$2.50
D
$3.00
35

What is the constant of variation, k, of the line y=kx through (3,18) and (5,30)?

A
Option
Option A
B
Option
Option B
C
3
D
6
36

An account is opened with $7,595.96 with a rate of increase of 2% per year. After 1 year, the bank account contains $7,746.90. Assuming no deposits or withdrawals are made, which equation can be used to find y, the amount of money in the account after x years? (Round money values to the nearest penny.)

A
y = 7,746.90(1.02)x
B
y = 7,746.90(0.02)x
C
y = 7,595.96(1.02)x
D
y = 7,595.96(0.02)x
37

Line QR goes through points Q(0, 1) and R(2, 7). Which equation represents line QR?

A
y – 1 = 6x
B
y – 1 = 3x
C
y – 7 = 2x – 6
D
y – 7 = x – 2
38

Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?

A
y – 12 = –5(x + 2)
B
y – 12 = 2(x + 2)
C
y + 12 = 2(x – 2)
D
y + 12 = –5(x – 2)

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