AnswersAZ-College Prep Math BThe Quadratic Formula

The Quadratic Formula — Unit test Answers

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What is the value of i 97 – i?

A
–i
B
0
C
–2i
D
i Superscript 96
Option D
3

Use the zero product property to find the solutions to the equation x2 – 9 = 16.

A
x = –3 or x = 3
B
x = –6 or x = –3
C
x = –5 or x = 5
D
x = 7 or x = 1
4

For what values of m does the graph of y = mx2 – 5x – 2 have no x-intercepts?

A
m greater-than negative StartFraction 25 Over 8 EndFraction
Option A
B
m less-than negative StartFraction 25 Over 8 EndFraction
Option B
C
m less-than StartFraction 25 Over 8 EndFraction
Option C
D
m greater-than StartFraction 25 Over 8 EndFraction
Option D
6

Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x?

A
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction
Option A
B
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction 2 StartRoot 15 EndRoot Over 11 EndFraction
Option B
C
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot Over 11 EndFraction
Option C
D
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot i Over 11 EndFraction
Option D
8

What are the values of x in the equation x2 – 6x + 9 = 25?

A
x = –2 or x = 8
B
x = –1 or x = –11
C
x = 1 or x = 11
D
x = 2 or x = –8
10

Solve for in the equation .

Question illustration
A
x = negative 11 plus-or-minus StartFraction 25 Over 2 EndFraction
Option A
B
x = negative eleven-halves plus-or-minus StartFraction 25 Over 2 EndFraction
Option B
C
x = negative 11 plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option C
D
x = negative eleven-halves plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option D
11

If the discriminant of a quadratic equation is 4, which statement describes the roots?

A
There are two complex roots.
B
There are two real roots.
C
There is one real root.
D
There is one complex root.
13

Which property of multiplication is shown below? If x = 3 + 4i and y = 5 + 6i, x × y = y × x.

A
commutative property
B
identity property
C
distributive property
D
associative property
14

Use the zero product property to find the solutions to the equation x2 – x – 6 = 0.

A
x = –3 or x = –2
B
x = –3 or x = 2
C
x = –2 or x = 3
D
x = 2 or x = 3
15

Solve for in the equation .

Question illustration
A
x = 3 plus-or-minus StartRoot 23 EndRoot
Option A
B
x = 3 plus-or-minus StartRoot 51 EndRoot
Option B
C
x = 3 plus-or-minus StartRoot 41 EndRoot
Option C
D
x = 3 plus-or-minus StartRoot 5 EndRoot
Option D

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