AnswersNC-Math 4 CRAdding and Subtracting Matrices

Adding and Subtracting Matrices — Unit test Answers

15 verified answers
7

Rosa earns $12 per hour. In 7.5 hours, she will earn x dollars. Which is a valid proportion that can be used to solve the problem?

A
StartFraction x over 12 EndFraction = StartFraction 1 over 7.5 EndFraction
Option A
B
StartFraction 1 over 12 EndFraction = StartFraction x over 7.5 EndFraction
Option B
C
StartFraction 12 over 1 EndFraction = StartFraction x over 7.5 EndFraction
Option C
D
StartFraction 12 over 1 EndFraction = StartFraction 7.5 over x EndFraction
Option D
9

Inez has a phone card. The graph shows the number of minutes that remain on her phone card after a certain number of days. The slope of the line that represents the data is –50, and the y-intercept is 850. What do the slope and y-intercept represent in Inez’s situation?

Question illustration
A
The y-intercept indicates that the phone card started with 850 minutes. The slope indicates that 50 minutes were used per day.
B
The y-intercept indicates that the phone card started with 50 minutes. The slope indicates that 850 minutes were used per day.
C
The slope indicates that the phone card started with 850 minutes. The y-intercept indicates that 50 minutes were added per day.
D
The slope indicates that the phone card started with 50 minutes. The y-intercept indicates that 850 minutes were added per day.
12

Which equation represents the linear function that is shown on the graph below?

Question illustration
A
y = one-half x + 4
Option A
B
y = one-half x minus 2
Option B
C
y = 4 x minus 2
Option C
D
y = negative 2 x + 4
Option D
14

Based on the graph of the line below, which describes the relationship between the value of the y-intercept and the value of the slope?

Question illustration
T
The y-intercept is 3, and the slope is .
Option T
T
The y-intercept is , and the slope is 3.
Option T
T
The y-intercept is 3, and the slope is 3.
T
The y-intercept is , and the slope is .
Option T
15

The linear equation when b = 5 and m = –2 is

A
y = 5x – 2.
B
y = 5x + 2.
C
y = –2x – 5.
D
y = –2x + 5.

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