AnswersNY-Algebra I Term 2 HillcrestFactoring Trinomials: a = 1 (Continued)

Factoring Trinomials: a = 1 (Continued) — Unit test Answers

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What is the product?

Question illustration
A
negative 81 t squared minus 16
Option A
B
negative 81 t squared + 16
Option B
C
negative 81 t squared minus 72 t + 16
Option C
D
negative 81 t squared + 72 t + 16
Option D
3

What is the difference of the two polynomials?(7y2 + 6xy) – (–2xy + 3)

A
7y2 + 4xy – 3
B
7y2 + 8xy – 3
C
7y2 + 4xy + 3
D
7y2 + 8xy + 3
4

What is the factored form of the polynomial?x2 − 15x + 36

A
(x − 4)(x − 9)
B
(x − 3)(x − 12)
C
(x + 4)(x + 9)
D
(x + 3)(x + 12)
5

Armando used algebra tiles to represent the product .

Question illustration
A
He used the algebra tiles correctly.
B
He did not represent the two original factors correctly.
C
The signs on some of the products are incorrect.
D
Some of the products do not show the correct powers of x.
6

Which expression is equivalent to 64y18 – 1000z6?

A
(4y6)3 – (10z2)3
B
(16y6)3 – (10z2)3
C
(16y6)3 – (100z2)3
D
(4y6)3 – (100z2)3
8

Which is equivalent to , and what type of special product is it?

Question illustration
A
; a perfect square trinomial
Option A
B
; the difference of squares
Option B
C
; a perfect square trinomial
Option C
D
; the difference of squares
Option D
12

What is the product?

Question illustration
A
2 x squared minus 3
Option A
B
2 x squared + 6 x
Option B
C
2 x squared + 5 x minus 3
Option C
D
2 x squared + 6 x minus 3
Option D
13

What is the factored form of the polynomial?z2 − 10z + 25

A
(z − 5)(z − 5)
B
(z + 5)(z + 5)
C
(z − 2)(z + 5)
D
(z + 2)(z − 5)
14

A polynomial is factored using algebra tiles.

Question illustration
A
(x − 1) and (x + 3)
B
(x + 1) and (x − 3)
C
(x − 2) and (x + 3)
D
(x + 2) and (x − 3)
15

Omar grouped the terms and factored the GCF out of the groups of the polynomial 3x3 – 15x2 – 4x + 20. His work is shown.Step 1: (3x3 – 15x2) + (–4x + 20)Step 2: 3x2(x – 5) + 4(–x + 5)

A
Omar should realize that his work shows that the polynomial is prime.
B
Omar should go back and regroup the terms in Step 1 as (3x3 – 15x2) – (4x + 20).
C
In Step 2, Omar should factor only out of the first expression.
D
Omar should factor out a negative from one of the groups so the binomials will be the same.

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