AnswersPBCSD_Grade_Forgiveness_1200330_Algebra 2_S1_2024Radical Equations and Extraneous Roots

Radical Equations and Extraneous Roots — Unit test Answers

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Which graph represents ?

Question illustration
A
On a coordinate plane, a cubic function has an inflection point at (0, negative 2).
Option A
B
On a coordinate plane, a cubic function has an inflection point at (negative 2, 0)
Option B
C
On a coordinate plane, a cubic function has an inflection point at (0, 2).
Option C
D
On a coordinate plane, a cubic function has an inflection point at (2, 0).
Option D
3

What is the following product? Assume

Question illustration
A
x StartRoot x EndRoot
Option A
B
RootIndex 12 StartRoot x Superscript 5 EndRoot
Option B
C
x (RootIndex 12 StartRoot x Superscript 5 EndRoot)
Option C
D
x6
4

What is the solution of ?

Question illustration
A
x = –10
B
x = 3
C
x = –10 or x = 3
D
no solution
5

What is the following simplified product? Assume

Question illustration
A
3 x StartRoot 6 x EndRoot + x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared + 8 x Superscript 5 Baseline StartRoot 10 x EndRoot
Option A
B
3 x StartRoot 6 x EndRoot + x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared StartRoot 2 EndRoot + 8 x Superscript 5 Baseline StartRoot 10 EndRoot
Option B
C
3 x StartRoot 6 x EndRoot minus x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared StartRoot 2 EndRoot minus 8 x Superscript 5 Baseline StartRoot 10 EndRoot
Option C
D
3 x StartRoot 6 x EndRoot minus x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x squared StartRoot 2 x EndRoot minus 8 x Superscript 5 Baseline StartRoot 10 x EndRoot
Option D
6

Which expression is equivalent to ?

Question illustration
A
StartFraction x Superscript one-half baseline Over y z squared EndFraction
Option A
B
StartFraction x Superscript one-half baseline Over y Superscript one-fourth Baseline z squared EndFraction
Option B
C
StartFraction y Superscript one-half Baseline Over x z squared EndFraction
Option C
D
StartFraction x z squared Over y Superscript one-half EndFraction
Option D
7

What is the simplified form of the following expression? Assume .

Question illustration
A
StartFraction RootIndex 5 StartRoot 10 x EndRoot Over 3 x EndFraction
Option A
B
StartFraction RootIndex 5 StartRoot 30 EndRoot Over 3 x EndFraction
Option B
C
StartFraction RootIndex 5 StartRoot 120 x cubed EndRoot Over 3 x EndFraction
Option C
D
StartFraction RootIndex 5 StartRoot 810 x cubed EndRoot Over 3 x EndFraction
Option D
9

Which function represents the following graph?

Question illustration
A
y = StartRoot x minus 3 EndRoot + 3
Option A
B
y = StartRoot x + 3 EndRoot + 3
Option B
C
y = RootIndex 3 StartRoot x minus 3 EndRoot + 3
Option C
D
y = RootIndex 3 StartRoot x + 3 EndRoot + 3
Option D
10

Which function has a domain of and a range of ?

Question illustration
A
y = StartRoot x minus 5 EndRoot + 3
Option A
B
y = StartRoot x + 5 EndRoot minus 3
Option B
C
y = negative StartRoot x minus 5 EndRoot + 3
Option C
D
y = negative StartRoot x + 5 EndRoot minus 3
Option D
12

Which of the following is the graph of ?

Question illustration
A
On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = negative 1.
Option A
B
On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.
Option B
C
On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at y = 1.
Option C
D
On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at y = negative 1.
Option D
13

Which expression is equivalent to ?

Question illustration
A
Negative 4 x Superscript 4 Baseline y Superscript 6
Option A
B
Negative 8 x Superscript 4 Baseline y Superscript 6
Option B
C
StartFraction 4 x Superscript 4 Baseline Over y Superscript 6 EndFraction
Option C
D
StartFraction 8 x Superscript 4 Baseline Over y Superscript 6 Baseline EndFraction
Option D
14

What is the following product? Assume

Question illustration
A
6 y squared StartRoot 10 EndRoot + 12 StartRoot 5 y EndRoot
Option A
B
6 StartRoot 10 EndRoot + 12 StartRoot 5 y EndRoot
Option B
C
6 y squared StartRoot 10 EndRoot + 4 StartRoot 5 y EndRoot
Option C
D
3 y squared StartRoot 10 EndRoot + 12 StartRoot 5 y EndRoot
Option D

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