AnswersCrowley Summer 26 Credit Recovery Algebra 2 ASolving Systems of Equations in Three Variables

Solving Systems of Equations in Three Variables — Unit test Answers

15 verified answers
3

Subtract 15mn – 22m +2n from 14mn – 12m +7n.

A
–mn + 10m + 5n
B
–mn – 34m + 5n
C
–mn – 34m + 9n
D
29mn – 34m + 9n
4

Which expression is equivalent to 64y18 – 1000z6?

A
(4y6)3 – (10z2)3
B
(16y6)3 – (10z2)3
C
(16y6)3 – (100z2)3
D
(4y6)3 – (100z2)3
5

Which expression is equivalent to ?

Question illustration
A
mc014-2.jpg
Option A
B
mc014-3.jpg
Option B
C
mc014-4.jpg
Option C
D
mc014-5.jpg
Option D
7

Omar grouped the terms and factored the GCF out of the groups of the polynomial 3x3 – 15x2 – 4x + 20. His work is shown.Step 1: (3x3 – 15x2) + (–4x + 20)Step 2: 3x2(x – 5) + 4(–x + 5)

A
Omar should realize that his work shows that the polynomial is prime.
B
Omar should go back and regroup the terms in Step 1 as (3x3 – 15x2) – (4x + 20).
C
In Step 2, Omar should factor only out of the first expression.
D
Omar should factor out a negative from one of the groups so the binomials will be the same.
9

Which expression is equivalent to ?

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
10

Miguel stated that any monomial can be a cube root. Sylvia disagreed and said that a monomial cube root must have exponents divisible by 3. Who is correct, and why?

A
Sylvia is correct. Any variable term, when it is cubed, always has an exponent divisible by 3.
B
Miguel is correct. Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents divisible by 3.
C
Sylvia is correct. In order for the cube to have exponents that are divisible by 3, the cube root has to be divisible by 3.
D
Miguel is correct. Sylvia confused the perfect square root with the perfect cube root.
12

Which product of prime polynomials is equivalent to 4x5 – 6x4 + 4x3 – 6x2?

A
2x2(x2 + 1)(2x – 3)
B
2x2(x2 – 1)(2x + 3)
C
x2(x2 + 1)(2x – 3)
D
2(x2 – 1)(2x + 3)
13

What is the factorization of g3 – 125?

A
(g– 5)(g2 + 5g + 10)
B
(g – 25)(g2 + 25g + 625)
C
(g – 5)(g2 + 5g + 25)
D
(g – 25)(g2 + 5g + 125)
15

Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.Step 1: (6x3 – 22x2) – (9x + 33)Step 2: 2x2(3x – 11) – 3(3x + 11)

A
Marisol should realize that her work shows that the polynomial is prime.
B
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).
C
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).
D
Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).

Did you find these answers helpful?