AnswersGA-GSE Pre-CalculusComposition of Functions and Modeling

Composition of Functions and Modeling — Unit test Answers

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Given r(x) = , which represents a domain restriction on r(x) and the corresponding inverse function?

Question illustration
A
x > 4; r–1(x) =
Option A
B
x > 4; r–1(x) =
Option B
C
x > –4; r–1(x) =
Option C
D
x > –4; r–1(x) =
Option D
26

Consider the function h(x) =x2 – 12x + 58.Which represents a domain restriction and the corresponding inverse function?

A
x ≥ 6; h–1(x) =
Option A
B
x ≥ 6; h–1(x) =
Option B
C
x ≥ 12; h–1(x) =
Option C
D
x ≥ 12; h–1(x) =
Option D
28

Let a and b be real numbers where a b 0. Which of the following functions could represent the graph below?

Question illustration
A
f(x) = x(x – a)2(x – b)4
B
f(x) = x(x – a)3(x – b)2
C
f(x) = x4(x – a)(x – b)2
D
f(x) = x2(x – a)5(x – b)
29

Review the graph of function g(x).

Question illustration
A
–5
B
Negative one-half
Option B
C
2
D
3
31

Which statement describes how the graph of a function, h(x), and its inverse, h‒1(x), are related?

A
The line y = ‒x is the perpendicular bisector of each segment connecting a point on h(x) to the corresponding point on h‒1(x).
B
The line y = x is the perpendicular bisector of each segment connecting a point on h(x) to the corresponding point on h‒1(x).
C
The graph of the inverse of h(x) is a reflection over the line y = 0 of the graph of h(x).
D
The y-axis is the perpendicular bisector of each segment connecting a point on h(x) to the corresponding point on h‒1(x).
32

If the interval (a, ∞) describes all values of x for which the graph of is decreasing, what is the value of a?

Answer not available
34

Review the table of values for function f(x).

Question illustration
A
–8
B
–7
C
StartFraction 1 Over 8 EndFraction
Option C
D
1
35

What are the additive and multiplicative inverses of h(x) = x – 24?

A
additive inverse: j(x) = x + 24; multiplicative inverse: k(x) =
Option A
B
additive inverse: j(x) = ; multiplicative inverse: k(x) = –x + 24
Option B
C
additive inverse: j(x) = –x + 24; multiplicative inverse: k(x) =
Option C
D
additive inverse: j(x) = –x + 24; multiplicative inverse: k(x) = x + 24
36

Which statement best compares the graphs of and ?

Question illustration
A
The two graphs are exactly the same.
B
The open and closed circles are reversed.
C
The graph of is shifted up compared to the graph of , and the open and closed circles are reversed.
Option C
D
The graph of is shifted up compared to the graph of , and the open and closed circles are the same.
Option D
37

Consider the function.f(x) = x2 + 3Which answer pairs a possible domain restriction that if placed upon f(x) would impact f–1(x) as shown?

A
f(x) domain: x ≥ 3f–1(x) domain: x ≥ 3
B
f(x) domain: x ≥ 3f–1(x) range: y ≥ 3
C
f(x) domain: x ≥ 0f–1(x) domain: x ≥ 0
D
f(x) domain: x ≥ 0f–1(x) range: y ≥ 0
38

Marin writes the functions m(x) = and n(x) = .Which equation must be true for m(x) and n(x) to be inverse functions?

Question illustration
A
StartStartFraction 3 (StartFraction 3 x Over x + 7 EndFraction) OverOver (StartFraction 3 x Over x + 7 EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 7 x Over 3 minus x EndFraction) OverOver 3 minus (StartFraction 7 x Over 3 minus x EndFraction) EndEndFraction = x
Option A
B
StartStartFraction 3 (StartFraction 7 x Over 3 minus x EndFraction) OverOver (StartFraction 7 x Over 3 minus x EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 3 x Over x + 7 EndFraction) OverOver 3 minus (StartFraction 3 x Over x + 7 EndFraction) EndEndFraction = x
Option B
C
StartStartFraction 3 (StartFraction 3 x Over x + 7 EndFraction) OverOver (StartFraction 3 x Over x + 7 EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 7 x Over 3 minus x EndFraction) OverOver 3 minus (StartFraction 7 x Over 3 minus x EndFraction) EndEndFraction = 0
Option C
D
StartStartFraction 3 (StartFraction 7 x Over 3 minus x EndFraction) OverOver (StartFraction 7 x Over 3 minus x EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 3 x Over x + 7 EndFraction) OverOver 3 minus (StartFraction 3 x Over x + 7 EndFraction) EndEndFraction = 0
Option D
39

Let q(t) = 29t and r(t) = .Which method could be the first step in proving that q(t) and r(t) are inverse functions?

Question illustration
A
Replace the t in the expression for q(t) with , and replace the t in the expression for r(t) with 29t.
Option A
B
Replace the 29t in the expression for q(t) with t, and replace the in the expression for r(t) with t.
Option B
C
Replace the t in the expression for q(t) with 29t, and replace the t in the expression for r(t) with .
Option C
D
Replace the 29t in the expression for q(t) with , and replace the in the expression for r(t) with 29t.
Option D
40

Study the graphs of f(x) and g(x).

Question illustration
A
Vertical stretch followed by a translation 1 unit left, so g(x) = f.
Option A
B
Vertical stretch followed by a translation 1 unit right, so g(x) = f.
Option B
C
Horizontal stretch followed by a translation 1 unit left, so g(x) = f.
Option C
D
Horizontal stretch followed by a translation 1 unit right, so g(x) = f.
Option D

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