AnswersSLPS-1200710-Mathematics for College Algebra - S2 - GFSynthetic Division and the Remainder Theorem

Synthetic Division and the Remainder Theorem — Unit test Answers

15 verified answers
1
Free Preview

If f(–5) = 0, what are all the factors of the function ? Use the Remainder Theorem.

Question illustration
A
(x – 2)(x + 5)(x – 3)
B
(x + 2)(x – 5)(x + 3)
C
(x – 2)(x + 5)
D
(x + 2)(x – 5)
2
Free Preview

What are the solutions of the equation (x + 2)2 + 12(x + 2) – 14 = 0? Use u substitution and the quadratic formula to solve.

A
x = negative 8 plus-or-minus 5 StartRoot 2 EndRoot
Option A
B
x = negative 6 plus-or-minus 5 StartRoot 2 EndRoot
Option B
C
x = negative 4 plus-or-minus 5 StartRoot 2 EndRoot
Option C
D
x = negative 2 plus-or-minus 5 StartRoot 2 EndRoot
Option D
6

Which polynomial function could be represented by the graph below?

Question illustration
A
f(x) = x2 + x – 2
B
f(x) = 2x2 + 2x – 4
C
f(x) = x2 – x – 2
D
f(x) = 2x2 –2x – 4
7

If (x + k) is a factor of f(x), which of the following must be true?

A
f(k) = 0
B
f(–k) = 0
C
A root of f(x) is x = k.
D
A y intercept of f(x) is x = –k.
9

What are the solutions of the equation x4 – 5x2 – 36 = 0? Use factoring to solve.

A
x = ±2 and x = ±3
B
x = ±2i and x = ±3
C
x = ±2 and x = ±3i
D
x = ±2i and x = ±3i
10

Which expression is a difference of cubes?

A
mc014-1.jpg
Option A
B
mc014-2.jpg
Option B
C
mc014-3.jpg
Option C
D
mc014-4.jpg
Option D
11

What is the end behavior of the graph of the polynomial function f(x) = –x5 + 9x4 – 18x3?

A
As , and as , .
Option A
B
As , and as , .
Option B
C
As , and as , .
Option C
D
As , and as , .
Option D
12

What is the cube root of

Question illustration
A
mc009-2.jpg
Option A
B
mc009-3.jpg
Option B
C
mc009-4.jpg
Option C
D
mc009-5.jpg
Option D
14

Which statement best describes the equation x5 + x3 – 14 = 0?

A
The equation is quadratic in form because it is a fifth-degree polynomial.
B
The equation is quadratic in form because the difference of the exponent of the lead term and the exponent of the middle term is 2.
C
The equation is not quadratic in form because it cannot be rewritten as a second-degree polynomial.
D
The equation is not quadratic in form because the exponent of the lead term is not the square of the exponent of the middle term.
15

What is the factored form of ?

Question illustration
A
mc022-2.jpg
Option A
B
mc022-3.jpg
Option B
C
mc022-4.jpg
Option C
D
mc022-5.jpg
Option D

Did you find these answers helpful?