AnswersMO-Algebra II A-CRPerforming Operations with Complex Numbers

Performing Operations with Complex Numbers — Unit test Answers

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21
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What is the rectangular form of the parametric equations x = 4 cos t and y = 5 sin t, where 0 ≤ t ≤ 2π?

A
StartFraction x squared Over 25 EndFraction + StartFraction y squared Over 16 EndFraction = 1
Option A
B
StartFraction x squared Over 16 EndFraction + StartFraction y squared Over 25 EndFraction = 1
Option B
C
StartFraction x squared Over 5 EndFraction + StartFraction y squared Over 4 EndFraction = 1
Option C
D
StartFraction x squared Over 4 EndFraction + StartFraction y squared Over 5 EndFraction = 1
Option D
22
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Which graph represents the parametric equations x = t2 + 2t and y = –t, where –4 ≤ t ≤ 1?

A
On a coordinate plane, a curve starts at (3, negative 1), curves up through (0, 0) to (negative 1, 1), and curves up through (0, 2) and (3, 3).
Option A
B
On a coordinate plane, a curve starts at (negative 1, 1) and curves down through (0, 0) and (8, negative 2).
Option B
C
On a coordinate plane, a curve starts at (3, 1), curves down through (0, 0) to (negative 1, negative 1), and then curves down through (0, negative 2) to (8, negative 4).
Option C
D
Option
Option D
25

Which is the equation of an asymptote of the hyperbola whose equation is = 1?

Question illustration
A
y = −3x − 5
B
y = −3x − 7
C
y = 3x − 5
D
y = 3x + 7
26

A soccer ball on the ground is kicked with an initial velocity of 37 feet per second at an elevation angle of 70°. Which parametric equations represent the path of the soccer ball?

A
x(t) = 37cos(70o)t and y(t) = –16t2 + 37sin(70o)t
B
x(t) = 37sin(70o)t and y(t) = –16t2 + 37cos(70o)t
C
x(t) = 37cos(70o)t and y(t) = –16t2 + sin(70o)t + 37
D
x(t) = 37sin(70o)t and y(t) = –16t2 + cos(70o)t + 37
29

Question text not available

Question illustration
A
x = −4.6 and x = 4.6
B
x = −3.5 and x = 3.5
C
y = −4.6 and y = 4.6
D
y = −3.5 and y = 3.5
30

Which graph represents the parametric equations x = 1 – t2 and y = 2t, where 0 ≤ t ≤ 5?

A
On a coordinate plane, a curve starts at (1, 0) and curves up through (0, 2) to (negative 24, 10).
Option A
B
On a coordinate plane, a curve starts at (1, 0) and curves down through (0, negative 2) to (negative 24, negative 10).
Option B
C
On a coordinate plane, a curve starts at (1, 0) and curves down through (2, negative 2) to (26, negative 10).
Option C
D
On a coordinate plane, a curve starts at (1, 0) and curves up through (2, 2) to (26, 10).
Option D
32

What is the positive slope of the asymptote of = 1? The positive slope of the asymptote is .

Answer not available

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