Answers230CR GeometryArea and Perimeter of Triangles

Area and Perimeter of Triangles — Unit test Answers

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The law of cosines is used to find the value of m.

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A
13
B
14
C
43
D
45
22
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A parallelogram has side lengths of 4 and 6 and an angle of measure 55°.Law of cosines: a2 = b2 + c2 – 2bccos(A)

Question illustration
A
3
B
5
C
6
D
7
23

Two students stand 1 yard apart and measure their respective angles of elevation to the top of a tree. Student A measures the angle to be 57°, and Student B measures the angle to be 46°.Law of sines:

Question illustration
A
3.0 yards
B
3.2 yards
C
3.8 yards
D
4.4 yards
24

Heron’s formula: Area =

Question illustration
A
square units
Option A
B
square units
Option B
C
square units
Option C
D
square units
Option D
25

Use the law of sines to find the value of a.Law of sines:

Question illustration
A
2.4 cm
B
2.7 cm
C
3.0 cm
D
3.3 cm
27

What is the area of triangle ABC? Round to the nearest square unit.

Question illustration
A
8 square units
B
15 square units
C
33 square units
D
618 square units
28

Triangle PQR has sides measuring 9 feet and 10 feet and a perimeter of 24 feet. What is the area of triangle PQR? Round to the nearest square foot.Heron’s formula: Area

Question illustration
A
6 square feet
B
7 square feet
C
19 square feet
D
22 square feet
29

The average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year, m, can be modeled by the equation , where m = 0 represents January 1, m = 1 represents February 1, m = 2 represents March 1, and so on. Which equation also models this situation?

Question illustration
A
t = negative 35 sine (StartFraction pi Over 6 EndFraction m) + 55
Option A
B
t = negative 35 sine (StartFraction pi Over 6 EndFraction (m + 3)) + 55
Option B
C
t = 35 sine (StartFraction pi Over 6 EndFraction m) + 55
Option C
D
t = 35 sine (StartFraction pi Over 6 EndFraction (m + 3)) + 55
Option D

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