Question 2 • FL-1200330-Algebra 2 Sem 2 - Flex
There are 3 + 4 + 5 = 12 electives, so the total number of ways to choose 2 is 12 × 11 ÷ 2 = 66. To choose one computer elective and one art elective, there are 5 × 3 = 15 possible pairs. Thus, the probability is 15 ÷ 66 ≈ 0.22727, which is choice C, 0.22727.
AI-written and checked against the verified answer.