AnswersMathematics III ASquare Root Functions

Square Root Functions — Unit test Answers

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Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x?

A
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction
Option A
B
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction 2 StartRoot 15 EndRoot Over 11 EndFraction
Option B
C
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot Over 11 EndFraction
Option C
D
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot i Over 11 EndFraction
Option D
4

Which function has a vertex on the y-axis?

A
f(x) = (x – 2)2
B
f(x) = x(x + 2)
C
f(x) = (x – 2)(x + 2)
D
f(x) = (x + 1)(x – 2)
5

For what values of m does the graph of y = mx2 – 5x – 2 have no x-intercepts?

A
m greater-than negative StartFraction 25 Over 8 EndFraction
Option A
B
m less-than negative StartFraction 25 Over 8 EndFraction
Option B
C
m less-than StartFraction 25 Over 8 EndFraction
Option C
D
m greater-than StartFraction 25 Over 8 EndFraction
Option D
6

If , which inequality can be used to find the domain of f(x)?

Question illustration
A
StartRoot 4 x EndRoot greater-than-or-equal-to 0
Option A
B
4 x + 9 greater-than-or-equal-to 0
Option B
C
4 x greater-than-or-equal-to 0
Option C
D
StartRoot 4 x + 9 EndRoot + 2 greater-than-or-equal-to 0
Option D
7

Which expression is equivalent to (3 + 5i)2?

A
–16 + 30i
B
6 + 34i
C
–16 – 34i
D
16 + 30i
9

If the discriminant of a quadratic equation is 4, which statement describes the roots?

A
There are two complex roots.
B
There are two real roots.
C
There is one real root.
D
There is one complex root.
10

Which equation represents a graph with a vertex at (1, –6)?

A
y = 3x2 + 6x – 3
B
y = 3x2 – 6x – 3
C
y = 3x2 – 8x – 1
D
y = 3x2 – 3x – 6
11

Which statements about the function are true? Select three options.

A
The vertex of the function is at (–4,–15).
B
The vertex of the function is at (–3,–16).
C
The graph is increasing on the interval x > –3.
D
The graph is positive only on the intervals where x 1.
E
The graph is negative on the interval x < –4.
12

Which equation is y = –6x2 + 3x + 2 rewritten in vertex form?

A
y = negative 6 (x minus 1) squared + 8
Option A
B
y = negative 6 (x + one-fourth) squared + thirteen-eighths
Option B
C
y = negative 6 (x minus one-fourth) squared + nineteen-eighths
Option C
D
y = negative 6 (x minus one-half) squared + seven-halves
Option D
13

Solve for in the equation .

Question illustration
A
x = negative 11 plus-or-minus StartFraction 25 Over 2 EndFraction
Option A
B
x = negative eleven-halves plus-or-minus StartFraction 25 Over 2 EndFraction
Option B
C
x = negative 11 plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option C
D
x = negative eleven-halves plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option D
14

Which equation is the inverse of y = 7x2 – 10?

A
y = StartFraction plus-or-minus StartRoot x + 10 EndRoot Over 7 EndFraction
Option A
B
y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot
Option B
C
x = plus-or-minus StartRoot StartFraction x Over 7 EndFraction + 10 EndRoot
Option C
D
y = StartFraction plus-or-minus StartRoot x EndRoot Over 7 EndFraction plus-or-minus StartFraction StartRoot 10 EndRoot Over 7 EndFraction
Option D
15

Which equation is the inverse of y = x2 – 36?

A
y = plus-or-minus StartRoot x EndRoot + 6
Option A
B
y = plus-or-minus StartRoot x + 36 EndRoot
Option B
C
y = plus-or-minus StartRoot x EndRoot + 36
Option C
D
y = plus-or-minus StartRoot x squared + 36 EndRoot
Option D

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