Symmetry — Unit test Answers

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3

A point has the coordinates (m, 0) and m ≠ 0.Which reflection of the point will produce an image located at (0, –m)?

A
a reflection of the point across the x-axis
B
a reflection of the point across the y-axis
C
a reflection of the point across the line y = x
D
a reflection of the point across the line y = –x
4

Which rules could describe the rotation? Select two options.

A
R0, 90°
B
R0, 180°
C
R0, 270°
D
(x, y) → (–y, x)
E
(x, y) → (y, –x)
5

Which statement describes the order of rotational symmetry for an isosceles triangle?

A
An isosceles triangle has an order 0 rotational symmetry because there is no angle at which it can be rotated onto itself.
B
An isosceles triangle has an order 1 rotational symmetry because it does not have all congruent angles.
C
An isosceles triangle has an order 2 rotational symmetry because it has 1 pair of congruent angles.
D
An isosceles triangle has an order 3 rotational symmetry because it has 3 angles.
6

Square PQRS is transformed as shown on the graph.

Question illustration
A
R0, 90°
B
R0, 180°
C
R0, 270°
D
R0, 360°
7

On a coordinate plane, 2 triangles are shown. The first triangle has points F (3, 2), H (4, 5), G (1, 2). The second triangle has points F prime (negative 2, 3), H prime (negative 5, 4), G prime (negative 2, 1).

Question illustration
A
Correct. He transformed the triangle according to the rule (x, y) → (–y, x).
B
Incorrect. He transformed the triangle according to the rule (x, y) → (y, –x)
C
Incorrect. He transformed the triangle according to the rule (x, y) → (–y, –x)
D
Incorrect. He transformed the triangle according to the rule (x, y) → (–x, –y)
8

A composition of transformations maps ΔKLM to ΔK"L"M".

Question illustration
A
a 90° rotation about point L
B
a 270° rotation about point L
C
a 90° rotation about point P
D
a 270° rotation about point P

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