Unit Test — Unit test Answers

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The graph of the function f(x) = (x + 2)(x − 4) is shown.

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A
all real values of x where x < −2
B
all real values of x where −2 < x < 4
C
all real values of x where 1 < x < 4
D
all real values of x where x < 0
2
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The function f(x) = –3x2 + 36x – 119 written in vertex form is f(x) = –3(x – 6)2 – 11. Which statements are true about the graph of f(x)? Select three options.The axis of symmetry is the line x = 6.The vertex of the graph is at (–6, –11).The parabola has a minimum.The parabola opens down.The value of h, when the equation is written in vertex form, is positive.

A
The axis of symmetry is the line x = 6.
B
The vertex of the graph is at (–6, –11).
C
The parabola has a minimum.
D
The parabola opens down.
E
The value of h, when the equation is written in vertex form, is positive.
3

What is the y-value of the vertex of the function f(x)=−(x−3)(x+11)?

A
−8
B
−4
C
33
D
49
4

Which translation maps the graph of the function f(x) = x2 onto the function g(x) = x2 − 6x + 6?

A
left 3 units, down 3 units
B
right 3 units, down 3 units
C
left 6 units, down 1 unit
D
right 6 units, down 1 unit
5

Which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = x2 – 10x +2?

A
right 5, down 23
B
left 5, down 23
C
right 5, up 27
D
left 5, up 27
6

The steps in writing f(x)=18x+3x2 in vertex form are shown, but a value is missing in the last step.Write the function in standard form. Factor a out of the first two terms. f(x)=3(x2+6x)Form a perfect square trinomial. f(x)=3(x2+6x+9)−3(9) Write the trinomial as a binomial squared. f(x)=3(x+___)2−27

Question illustration
A
3
B
6
C
9
D
18
7

What are the x-intercepts of the graph of the function f(x) = x2 + 5x − 36?

A
(−4, 0) and (9, 0)
B
(4, 0) and (−9, 0)
C
(−3, 0) and (12, 0)
D
(3, 0) and (−12, 0)
8

The function g(x) is a translation of f(x) = (x + 3)2 – 10. The axis of symmetry of g(x) is 5 units to the right of f(x) . Which function could be g(x)?

A
g(x) = (x – 2)2 + k
B
g(x) = (x + 8)2 + k
C
g(x) = (x – h)2 – 5
D
g(x) = (x – h)2 – 15
9

The function f(x) = –x2 – 4x + 5 is shown on the graph.

Question illustration
A
The domain of the function is all real numbers less than or equal to −2.
B
The domain of the function is all real numbers less than or equal to 9.
C
The range of the function is all real numbers less than or equal to −2.
D
The range of the function is all real numbers less than or equal to 9.
10

Which statements about the function are true? Select three options.

A
The vertex of the function is at (–4,–15).
B
The vertex of the function is at (–3,–16).
C
The graph is increasing on the interval x > –3.
D
The graph is positive only on the intervals where x 1.
E
The graph is negative on the interval x < –4.
11

The image shows a geometric representation of the function f(x) = x2 + 2x + 3 written in standard form.

Question illustration
A
f(x) = (x + 2)2 + 3
B
f(x) = (x2 + 2x)2 + 3
C
f(x) = (x + 1)2 + 2
D
f(x) = (x + 3)2 + 2x
12

Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x2 – 36x?

A
The graph of f(x) = x2 is widened.
B
The graph of f(x) = x2 is shifted right 4 units.
C
The graph of f(x) = x2 is shifted down 36 units.
D
The graph of f(x) = x2 is reflected over the x-axis.
13

What is the axis of symmetry of h(x) = 6x2 − 60x + 147?

A
x = −5
B
x = −3
C
x = 3
D
x = 5
14

What is the y-value of the vertex of the function f(x)=−(x+8)(x−14)?

A
3
B
6
C
112
D
121
15

Which is the graph of the function f(x) = x2 + 2x + 3?

A
On a coordinate plane, a parabola opens up. It goes through (negative 2, 3), has a vertex at (negative 1, 2), and goes through (0, 3).
Option A
B
On a coordinate plane, a parabola opens up. It goes through (0, 3), has a vertex at (1, 2), and goes through (2, 3).
Option B
C
On a coordinate plane, a parabola opens up. It goes through (negative 4, 3), has a vertex at (negative 2, negative 1), and goes through (0, 3).
Option C
D
On a coordinate plane, a parabola opens up. It goes through (0, 3), has a vertex at (2, negative 1), and goes through (4, 3).
Option D

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