AnswersLJISD-TX-Algebra II-5th 6WKSRadical Equations and Extraneous Roots

Radical Equations and Extraneous Roots — Unit test Answers

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1
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What is the following quotient?

Question illustration
A
2 (RootIndex 3 StartRoot 3 EndRoot) minus RootIndex 3 StartRoot 18 EndRoot
Option A
B
2 (RootIndex 3 StartRoot 3 EndRoot) minus 3 (RootIndex 3 StartRoot 2 EndRoot)
Option B
C
3 (RootIndex 3 StartRoot 3 EndRoot) minus RootIndex 3 StartRoot 18 EndRoot
Option C
D
3 (RootIndex 3 StartRoot 3 EndRoot) minus 3 (RootIndex 3 StartRoot 2 EndRoot)
Option D
2
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What is the simplified form of the following expression?

Question illustration
A
StartRoot 3 EndRoot
Option A
B
9 StartRoot 3 EndRoot
Option B
C
11 StartRoot 3 EndRoot
Option C
D
15 StartRoot 3 EndRoot
Option D
3

Which function has a domain of and a range of ?

Question illustration
A
y = StartRoot x minus 5 EndRoot + 3
Option A
B
y = StartRoot x + 5 EndRoot minus 3
Option B
C
y = negative StartRoot x minus 5 EndRoot + 3
Option C
D
y = negative StartRoot x + 5 EndRoot minus 3
Option D
4

Jamal simplified the expression where and . Which describes the error Jamal made?

Question illustration
A
He should have written the square root of in the answer as , not .
Option A
B
He should have written the square root of in the answer as , not .
Option B
C
He should have written the 5 inside of the radical in the answer.
D
He should have written the 3 outside of the radical in the answer.
5

Which expression is equivalent to ? Assume and .

Question illustration
A
StartFraction a cubed b (RootIndex 3 StartRoot 15 b squared EndRoot) Over 2 c cubed EndFraction
Option A
B
StartFraction b (RootIndex 3 StartRoot 15 b EndRoot) Over 2 a squared c cubed EndFraction
Option B
C
StartFraction a cubed b (RootIndex 3 StartRoot 15 b squared EndRoot) Over 6 c cubed EndFraction
Option C
D
StartFraction b (RootIndex 3 StartRoot 15 b EndRoot) Over 2 a c EndFraction
Option D
6

If x is a positive integer, which expression is equivalent to ? Assume .

Question illustration
A
RootIndex 20 StartRoot x Superscript 7 EndRoot
Option A
B
x (RootIndex 20 StartRoot x cubed EndRoot)
Option B
C
StartFraction RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot Over x squared EndFraction
Option C
D
x cubed (RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot)
Option D
7

What is the solution of ?

Question illustration
A
x = –17
B
x = 13
C
x = 53
D
no solution
8

What is the simplified form of the following expression? Assume .

Question illustration
A
StartFraction RootIndex 5 StartRoot 10 x EndRoot Over 3 x EndFraction
Option A
B
StartFraction RootIndex 5 StartRoot 30 EndRoot Over 3 x EndFraction
Option B
C
StartFraction RootIndex 5 StartRoot 120 x cubed EndRoot Over 3 x EndFraction
Option C
D
StartFraction RootIndex 5 StartRoot 810 x cubed EndRoot Over 3 x EndFraction
Option D
9

What is the following product? Assume

Question illustration
A
x StartRoot x EndRoot
Option A
B
RootIndex 12 StartRoot x Superscript 5 EndRoot
Option B
C
x (RootIndex 12 StartRoot x Superscript 5 EndRoot)
Option C
D
x6
10

Which expression is equivalent to ?

Question illustration
A
StartFraction x Superscript one-half baseline Over y z squared EndFraction
Option A
B
StartFraction x Superscript one-half baseline Over y Superscript one-fourth Baseline z squared EndFraction
Option B
C
StartFraction y Superscript one-half Baseline Over x z squared EndFraction
Option C
D
StartFraction x z squared Over y Superscript one-half EndFraction
Option D
11

If y is a positive integer, for how many different values of y is a whole number?

Question illustration
A
1
B
2
C
6
D
15
12

What values of c and d make the equation true? Assume and

Question illustration
A
c = 1, d = 3
B
c = 1, d = 9
C
c = 2, d = 8
D
c = 2, d = 9
13

What is the following sum?

Question illustration
A
6 b squared (RootIndex 3 StartRoot 2 a EndRoot)
Option A
B
12 b squared (RootIndex 3 StartRoot 2 a EndRoot
Option B
C
6 b squared (RootIndex 6 StartRoot 2 a EndRoot)
Option C
D
12 b squared (RootIndex 6 StartRoot 2 a EndRoot)
Option D
14

What is the solution of ?

Question illustration
A
x = –10
B
x = 3
C
x = –10 or x = 3
D
no solution
15

The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is k times the mean distance from the sun as planet X, by what factor is the orbital period increased?

Question illustration
A
k Superscript one-third
Option A
B
k Superscript one-half
Option B
C
k Superscript two-thirds
Option C
D
k Superscript three-halves
Option D

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Radical Equations and Extraneous Roots — Unit…