AnswersMath 8Analyzing Solutions

Analyzing Solutions — Unit test Answers

2 verified answers
1
Free Preview

Ronin draws a square with a measure of inches on each side. The perimeter of his square is 96 inches. The equation below represents the perimeter of the square.What is the value of x?

Question illustration
A
16
B
22
C
24
D
26
2
Free Preview

Kari picked 23 bunches of flowers from her garden. Each bunch had the same number of flowers. After she gave 46 flowers away, she had 138 left. How many flowers were in each bunch?

A
3
B
4
C
6
D
8
3

What is the solution to the equation ?

Question illustration
A
x = 0.15
Option A
B
x = negative 0.15
Option B
C
x = negative 0.3
Option C
D
x = 0.3
Option D
4

Aanya wrote the four equations that are shown below.AB CDShe examined them, without solving them, to determine which has exactly one solution. Which of Aanya’s equations has exactly one solution?

Question illustration
A
6 x minus 8 = 4 (x minus 2) + 2 x
Option A
B
3 (x minus 1) + 2 x = 3 (x minus 1) + 2
Option B
C
7 x + 2 minus x = 6 (x + 2)
Option C
D
4 (x + 3) + x = 5 (x + 1) + 7
Option D
5

Katrina is solving the equation . Which equivalent equations might Katrina use? Check all that apply.

Question illustration
A
x minus 2 x minus 6 = 8 x + 12 minus x minus 4
Option A
B
x minus 2 x + 6 = 8 x + 12 minus x + 4
Option B
C
x minus 2 x minus 6 = 8 x + 12 minus x + 4
Option C
D
x minus 2 x + 3 = 8 x + 3 minus x + 4
Option D
E
Negative x minus 6 = 7 x + 8
Option E
F
Negative x + 6 = 7 x + 16
Option F
G
Negative x minus 6 = 7 x + 16
Option G
H
Negative x + 3 = 7 x + 7
Option H
6

To solve the equation, Antwan uses the distributive property, combines like terms, then uses the addition and subtraction properties of equality to isolate the variable term on one side of the equation and the constant term on the other side. What are the possible values of the constant after Antwan has completed these steps?

Question illustration
A
–3 or 3
B
–3 or 5
C
–20 or 5
D
–20 or 20
7

What is the value of x in the equation below? Round to the nearest hundredths place.

Question illustration
A
3.01
Option A
B
3.17
Option B
C
36.44
Option C
D
38.4
Option D
8

What is the value of x in the equation ?

Question illustration
A
1
B
2
C
3
D
5
9

What is the value of c in the equation ?

Question illustration
A
3 and one-sixth
Option A
B
7 and StartFraction 7 Over 12 EndFraction
Option B
C
12
D
17
10

Viktoriya solved an equation as shown below.She says that the equation has infinitely many solutions. Which describes Viktoriya’s error?

Question illustration
A
Viktoriya used the distributive property incorrectly when she found the solution.
B
Viktoriya should have said that the equation has no solution.
C
Viktoriya should have continued to solve the equation to find that .
Option C
D
Viktoriya should have said that the equation has one unique solution.
11

Which is a reasonable first step that can be used to solve the equation ?

Question illustration
A
Distribute the 3 to x + 2, and distribute the 5 to (2x – 3).
B
Combine 4x and x on the left side of the equation.
C
Apply the subtraction property of equality to move the 2 from the left to the right side of the equation.
D
Apply the addition property of equality to move the 3 from the right to the left side of the equation.
12

Three investors own a company. One partner owns of the company, while the second partner owns of the company. How much does the third partner own?

Question illustration
A
Two-thirds
Option A
B
StartFraction 7 Over 20 EndFraction
Option B
C
StartFraction 13 Over 20 EndFraction
Option C
D
StartFraction 17 Over 20 EndFraction
Option D
14

Identify the method that will be used in solving for x.

Question illustration
A
distributive property
B
multiplication property of equality
C
division property of equality
D
subtraction property of equality
15

Kamal solved an equation as shown below.What is the solution to Kamal’s equation?

Question illustration
A
–24
B
7
C
no solution
D
infinitely many solutions

Did you find these answers helpful?

Analyzing Solutions — Unit test Answers — Math 8