How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

In y = sec(x + 3) − 7, adding 3 inside the function shifts the graph 3 units left. Subtracting 7 outside the function shifts it 7 units down. Therefore, the graph is shifted 3 units left and 7 units down, which is choice C.

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