Unit Test — Unit test Answers

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On a coordinate plane, an absolute value graph has a vertex at (1, 3).

Question illustration
A
g(x) = |x + 1| + 3
B
g(x) = |x + 3| – 1
C
g(x) = |x – 1| + 3
D
g(x) = |x + 3| + 1
3

Johan found that the equation –2|8 – x| – 6 = –12 had two possible solutions: x = 5 and x = –11. Which explains whether his solutions are correct?

A
He is correct because both solutions satisfy the equation.
B
He is not correct because he made a sign error.
C
He is not correct because there are no solutions.
D
He is not correct because there is only one solution: x = 5.
13

Which statement is true about ?

Question illustration
A
The graph of f(x) has a vertex of (–4, 6).
B
The graph of f(x) is a horizontal stretch of the graph of the parent function.
C
The graph of f(x) opens upward.
D
The graph of f(x) has a domain of x –6.
Option D
14

Which graph represents the function f(x) = |x| – 4?

A
On a coordinate plane, an absolute value graph has a vertex at (0, 4).
Option A
B
On a coordinate plane, an absolute value graph has a vertex at (negative 4, 0).
Option B
C
On a coordinate plane, an absolute value graph has a vertex at (0, negative 4).
Option C
D
On a coordinate plane, an absolute value graph has a vertex at (4, 0).
Option D
15

What is the solution to the inequality ?

Question illustration
A
–3 > n > –2
B
2 < n < 3
C
n –2
D
n 3
16

Which number line represents the solutions to –2|x| = –6?

A
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 6 and one at negative 2.
Option A
B
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 8 and one at negative 4.
Option B
C
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 4 and one at 4.
Option C
D
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 3 and one at 3.
Option D
19

What is the solution to the inequality ?

Question illustration
A
–7 < x < –1
B
1 < x < 7
C
x < –7 or x < –1
D
x > 1 or x < 7
20

What is the range of the function g(x) = |x – 12| – 2?

A
{y | y > –2}
B
{y | y > –2}
C
{y | y > 12}
D
{y | y > 12}

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