AnswersAlgebra 2-2nd Semester-CR KCKPS 02101040Unit Test

Unit Test — Unit test Answers

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1
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Which expression is equivalent to the following complex fraction?

Question illustration
A
StartFraction negative 2 y + 5 x Over 3 x minus 2 y EndFraction
Option A
B
StartFraction 3 x minus 2 y Over negative 2 y + 5 x EndFraction
Option B
C
StartFraction x squared y squared Over (negative 2 y + 5 x) (3 x minus 2 y) EndFraction
Option C
D
StartFraction (negative 2 y + 5 x) (3 x minus 2 y) Over x squared y squared EndFraction
Option D
2
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What are the excluded values of x for ?

Question illustration
A
x = –7, x = 4
B
x = –7, x = 5
C
x = –5, x = 7
D
x = –4, x = 7
3

The inverse variation equation shows the relationship for a cruise ship’s travel between the rate of travel, x, and the time to travel, y for a distance of 600 miles. What is the rate of travel in miles per hour (mph) if the trip takes 24 hours?

Question illustration
A
2.5 mph
B
25 mph
C
144 mph
D
14,400 mph
4

Mr. Knotts found the difference of the following expression. Which statement is true about Mr. Knotts’s work? Step 1: Step 2: Step 3: Step 4:

Question illustration
A
In step 1, he did not correctly factor the denominator.
B
In step 2, he did not use the correct common denominator.
C
In step 3, he did not distribute the negative sign when he subtracted.
D
In step 4, he did not correctly subtract the numerator.
5

What is the solution to the equation ?

Question illustration
A
y = –4 and y = 4
B
y = 0
C
all real numbers
D
no solution
6

How many extraneous solutions does the equation below have?

Question illustration
A
0
B
1
C
2
D
3
7

Which expression is equivalent to ?

Question illustration
A
mc007-2.jpg
Option A
B
mc007-3.jpg
Option B
C
mc007-4.jpg
Option C
D
mc007-5.jpg
Option D
8

How does the graph of compare to the graph of the parent function ?

Question illustration
A
g(x) is shifted 4 units right and 6 units up from f(x).
B
g(x) is shifted 4 units right and 6 units down from f(x).
C
g(x) is shifted 4 units left and 6 units up from f(x).
D
g(x) is shifted 4 units left and 6 units down from f(x).
9

The equation shows that the density of a particular substance equals a mass of 13 grams divided by the volume of the substance. What happens to the density as the volume approaches 0?

Question illustration
A
The density approaches infinity.
B
The density approaches 0.
C
The density approaches 1.
D
The density approaches 13.
10

What is the product?

Question illustration
A
StartFraction 4 n Over n + 1 EndFraction
Option A
B
StartFraction n Over n + 1 EndFraction
Option B
C
StartFraction 1 Over n + 1 EndFraction
Option C
D
StartFraction 4 Over n + 1 EndFraction
Option D
11

Which expression is equivalent to ?

Question illustration
A
StartFraction m minus 4 Over (m + 4) (m + 2) EndFraction
Option A
B
StartFraction (m + 4) (m + 2) Over m minus 4 EndFraction
Option B
C
StartFraction (m minus 4) (m + 2) Over m + 4 EndFraction
Option C
D
StartFraction m + 4 Over (m minus 4) (m + 2) EndFraction
Option D
12

Which graph represents the function ?

Question illustration
A
On a coordinate plane, a hyperbola and parabola are shown. The hyperbola has a curve in quadrants 1 and 2. The parabola opens down and has a vertex at (0, 0).
Option A
B
On a coordinate plane, a hyperbola and a cubic functions are shown. They hyperbola has curves in quadrants 1 and 3, and the cubic function goes through (0, 0).
Option B
C
On a coordinate plane, a hyperbola is shown. One curve is in quadrant 1 and the other curves goes through quadrants 2 and 4.
Option C
D
On a coordinate plane, a hyperbola is shown. Both curves open downward in quadrants 3 and 4.
Option D
13

Where are the vertical asymptotes for the following function located?

Question illustration
A
x = –4 and x = 6
B
x = –4 and x = 7
C
x = 4 and x = –6
D
x = 6 and x = 7
14

How can Ari simplify the following expression?

Question illustration
A
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerator by the reciprocal of the denominator.
B
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerators and multiply the denominators.
C
Divide the numerator and the denominator by a – 3. Then divide the numerator by the denominator.
D
Divide the numerator and the denominator by a – 3. Then simplify the numerator and simplify the denominator.
15

Which expression is equivalent to the expression below?

Question illustration
A
StartFraction 1 Over (m + 4) (m + 3) EndFraction
Option A
B
StartFraction 1 Over (m minus 4) (m minus 3) EndFraction
Option B
C
StartFraction m minus 4 Over m minus 3 EndFraction
Option C
D
StartFraction m + 3 Over m + 4 EndFraction
Option D
16

The excluded values of a rational expression are 2 and 5. Which of the following could be this expression?

A
mc024-1.jpg
Option A
B
mc024-2.jpg
Option B
C
mc024-3.jpg
Option C
D
mc024-4.jpg
Option D
17

The increase in a person’s body temperature T(t), above 98.6ºF, can be modeled by the function , where t represents time elapsed. What is the meaning of the horizontal asymptote for this function?

Question illustration
A
The horizontal asymptote of y = 0 means that the person’s temperature will approach 98.6ºF as time elapses.
B
The horizontal asymptote of y = 0 means that the person’s temperature will approach 0ºF as time elapses.
C
The horizontal asymptote of y = 4 means that the person’s temperature will approach 102.6ºF as time elapses.
D
The horizontal asymptote of y = 4 means that the person’s temperature will approach 4ºF as time elapses.
18

Which statement is true about the discontinuities of the function f(x)?

Question illustration
A
There are asymptotes at and .
Option A
B
There are holes at and .
Option B
C
There are asymptotes at and .
Option C
D
There are holes at and .
Option D
19

Which graph represents the function ?

Question illustration
A
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.
Option A
B
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.25.
Option B
C
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.
Option C
D
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.25.
Option D
20

Does the expression simplify to x?

Question illustration
A
No, because x3 – 1 can be factored as x(x2 – x + 1) and x2 – 1 can be factored as x(x – 1), so only x can be canceled.
B
Yes, because x3(x – 1) can be factored as x2(x – 1) and x2 – 1 can be factored as x(x – 1), so (x – 1) can be canceled.
C
No, because the –1 in the numerator and denominator is not a common factor and cannot be canceled.
D
Yes, because –1 in the numerator and denominator is a common factor and can be canceled.

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