Unit Test — Unit test Answers

25 verified answers
1
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Which expression is equivalent to ?

Question illustration
A
mc007-2.jpg
Option A
B
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Option B
C
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Option C
D
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Option D
2
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Which expression is equivalent to the following complex fraction?

Question illustration
A
StartFraction negative 2 y + 5 x Over 3 x minus 2 y EndFraction
Option A
B
StartFraction 3 x minus 2 y Over negative 2 y + 5 x EndFraction
Option B
C
StartFraction x squared y squared Over (negative 2 y + 5 x) (3 x minus 2 y) EndFraction
Option C
D
StartFraction (negative 2 y + 5 x) (3 x minus 2 y) Over x squared y squared EndFraction
Option D
3

What are the excluded values of x for ?

Question illustration
A
x = –7, x = 4
B
x = –7, x = 5
C
x = –5, x = 7
D
x = –4, x = 7
5

How can Ari simplify the following expression?

Question illustration
A
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerator by the reciprocal of the denominator.
B
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerators and multiply the denominators.
C
Divide the numerator and the denominator by a – 3. Then divide the numerator by the denominator.
D
Divide the numerator and the denominator by a – 3. Then simplify the numerator and simplify the denominator.
6

The cost of catering a dinner is $11.95 per person plus $25 for delivery and setup. Which statement is true about the graph of the function that represents the average cost per person?

A
The horizontal asymptote y = 0 represents that the cost per person approaches $0 as the number of people increases.
B
The horizontal asymptote y = 11.95 represents that the cost per person approaches $11.95 as the number of people increases.
C
The vertical asymptote x = 0 represents that the cost per person approaches $0 as the number of people increases.
D
The vertical asymptote x = 11.95 represents that the cost per person approaches $11.95 as the number of people increases.
7

What is the solution to the equation ?

Question illustration
A
y = –4 and y = 4
B
y = 0
C
all real numbers
D
no solution
9

Using V = lwh, what is an expression for the volume of the following prism?

Question illustration
A
StartFraction 4 (d minus 2) Over 3 (d minus 3)(d minus 4) EndFraction
Option A
B
StartFraction 4 d minus 8 Over 3 (d minus 4) squared EndFraction
Option B
C
StartFraction 4 Over 3 d minus 12 EndFraction
Option C
D
StartFraction 1 Over 3 d minus 3 EndFraction
Option D
10

What is the product?

Question illustration
A
StartFraction 4 n Over n + 1 EndFraction
Option A
B
StartFraction n Over n + 1 EndFraction
Option B
C
StartFraction 1 Over n + 1 EndFraction
Option C
D
StartFraction 4 Over n + 1 EndFraction
Option D
11

Which expression is equivalent to ?

Question illustration
A
StartFraction m minus 4 Over (m + 4) (m + 2) EndFraction
Option A
B
StartFraction (m + 4) (m + 2) Over m minus 4 EndFraction
Option B
C
StartFraction (m minus 4) (m + 2) Over m + 4 EndFraction
Option C
D
StartFraction m + 4 Over (m minus 4) (m + 2) EndFraction
Option D
12

Which expression is equivalent to the expression below?

Question illustration
A
StartFraction 1 Over (m + 4) (m + 3) EndFraction
Option A
B
StartFraction 1 Over (m minus 4) (m minus 3) EndFraction
Option B
C
StartFraction m minus 4 Over m minus 3 EndFraction
Option C
D
StartFraction m + 3 Over m + 4 EndFraction
Option D
14

Does the expression simplify to x?

Question illustration
A
No, because x3 – 1 can be factored as x(x2 – x + 1) and x2 – 1 can be factored as x(x – 1), so only x can be canceled.
B
Yes, because x3(x – 1) can be factored as x2(x – 1) and x2 – 1 can be factored as x(x – 1), so (x – 1) can be canceled.
C
No, because the –1 in the numerator and denominator is not a common factor and cannot be canceled.
D
Yes, because –1 in the numerator and denominator is a common factor and can be canceled.
19

Mr. Knotts found the difference of the following expression. Which statement is true about Mr. Knotts’s work? Step 1: Step 2: Step 3: Step 4:

Question illustration
A
In step 1, he did not correctly factor the denominator.
B
In step 2, he did not use the correct common denominator.
C
In step 3, he did not distribute the negative sign when he subtracted.
D
In step 4, he did not correctly subtract the numerator.
20

What is the difference?

Question illustration
A
StartFraction 2 (x + 6) Over (x + 4) (x minus 4) EndFraction
Option A
B
StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction
Option B
C
StartFraction x minus 3 Over (x + 5) (x minus 4) EndFraction
Option C
D
StartFraction negative 2 (x minus 6) Over (x + 4) (x minus 4) EndFraction
Option D

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