AnswersMISD-Geometry-RECOVERY-A-2019-2020Directed Line Segments and Modeling

Directed Line Segments and Modeling — Unit test Answers

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1
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Given: bisects ∠MRQ; ∠RMS ≅ ∠RQS

Question illustration
A
ΔMNR ≅ ΔMNS by ASA
B
ΔRMS ≅ ΔRQS by AAS
C
ΔSNQ ≅ ΔSNM by SSS
D
ΔQNR ≅ ΔMNR by HL
7

Triangle TVW is dilated according to the ruleDO,(x,y) to create the image triangle T'V'W', which is not shown.

Question illustration
A
T'(-3, 6) and V'(0, 3)
B
T'(-3, 6) and V'(0, 1)
C
T'(-1, 2) and V'(0, 3)
D
T'(-1, 2) and V'(0, 1)
8

The proof that ΔQPT ≅ ΔQRT is shown.Given: SP ≅ SRProve: ΔQPT ≅ ΔQRT

Question illustration
A
definition of perpendicular bisector
B
definition of congruence
C
reflexive property
D
substitution property
9

On a coordinate plane, Rectangles A B C D and E F G H are shown. The length of side A B is 6 units and the length of side B C is 3 units. The length of side E F is 8 units and the length of side F G is 4 units.

Question illustration
A
Yes, because corresponding sides are parallel and have lengths in the ratio
Option A
B
Yes, because both figures are rectangles and all rectangles are similar.
C
No, because the center of dilation is not at (0, 0).
D
No, because corresponding sides have different slopes.
11

Triangles J K L and M N R are shown.

Question illustration
A
KL ≅ NR
B
∠L ≅ ∠R
C
∠K ≅ ∠N
D
JK ≅ MN
12

Triangles R S T and V U T are connected at point T. Angles R S T and V U T are right angles. The length of side R S is 12 and the length of side S T is 16. The length of side T U is 8 and the length of U V is 6.

Question illustration
A
StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U
Option A
B
StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction = StartFraction R T Over V T EndFraction
Option B
C
StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction and angle S is-congruent-to angle U
Option C
D
StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction = StartFraction R T Over V T EndFraction
Option D
13

Triangles L M N and P O N connect at point N. Angles L M N and N O P are congruent.

Question illustration
A
because both triangles appear to be equilateral
B
because∠MNL and ∠ONP are congruent angles
C
because one pair of congruent corresponding angles is sufficient to determine similar triangles
D
because both triangles appear to be isosceles, ∠MLN ≅ ∠LMN, and ∠NOP ≅ ∠OPN
14

Point P is the center of dilation. Triangle A B C is dilated to create triangle A prime B prime C prime. The length of P A is 2 and the length of P B is 3. The Length of A A prime is 4 and the length of B B prime is 5.

Question illustration
A
Yes, it is an enlargement with a scale factor of 3.
B
Yes, it is an enlargement with a scale factor of .
Option B
C
No, it is not a dilation because the points of the image are not moved away from the center of dilation proportionally.
D
No, it is not a dilation because the sides of the image are proportionally reduced from the pre-image.
15

Consider the two triangles.

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
16

Read the proof.Given: AB ∥ DEProve: △ACB ~ △DCE

Question illustration
A
AA similarity theorem.
B
SSS similarity theorem.
C
AAS similarity theorem.
D
ASA similarity theorem.
17

is an altitude in triangle WXZ.

Question illustration
A
XWZ is an obtuse angle.
B
XWZ is a right angle.
C
XWZ is congruent to WXY.
D
XWZ is congruent to XZW.
18

Which pair of triangles can be proven congruent by SAS?

A
2 identical triangles are shown. The triangle is reflected across a line to form the second triangle.
Option A
B
2 identical triangles are shown. The triangle is rotated 90 degrees to form the second triangle.
Option B
C
2 identical triangles are shown. The triangle is reflected across a line and then rotated to form the second triangle.
Option C
D
2 identical triangles are shown. The triangle is rotated up and to the left 90 degrees to form the second triangle.
Option D

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