1
QuizMultiple Choice
Lab: Calorimetry and Specific Heat — Unit test
Question 1 • Chemistry A.1 - F26 - Jacob Metsker
The decomposition of calcium carbonate, CaCO3(s) CaO(s) + CO2(g), has the following values for free energy and enthalpy at 25.0°C. G = 130.5 kJ/molH = 178.3 kJ/molWhat is the entropy of the reaction? Use G = H – TS.
Answer
A
160.3 J/(molK)
B
47.8 J/(molK)
C
160.3 J/(molK)
D
1,912 J/(molK)