AnswersOH-Geometry BArea and Perimeter of Triangles

Area and Perimeter of Triangles — Unit test Answers

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1
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Law of sines:

Question illustration
A
only 90°
B
only 155°
C
20° and 110°
D
45° and 135°
3

Law of cosines: a2 = b2 + c2 – 2bccos(A)

Question illustration
A
92 = y2 + 192 – 2(y)(19)cos(41°)
B
y2 = 92 + 192 – 2(y)(19)cos(41°)
C
92 = y2 + 192 – 2(9)(19)cos(41°)
D
y2 = 92 + 192 – 2(9)(19)cos(41°)
7

Which equation can be used to find the length of ?

Question illustration
A
(10)sin(40o) = AC
B
(10)cos(40o) = AC
C
= AC
Option C
D
= AC
Option D
13

Which statements are true about triangle QRS? Select three options.

A
The side opposite ∠Q is RS.
B
The side opposite ∠R is RQ.
C
The hypotenuse is QR.
D
The side adjacent to ∠R is SQ.
E
The side adjacent to ∠Q is QS.
14

Law of sines:

Question illustration
A
15°
B
30°
C
45°
D
60°
15

Triangle V U W is shown. The length of side W V is 6 centimeters, the length of side W U is 3 StartRoot 3 EndRoot centimeters, and the length of side U V is 3 centimeters.

Question illustration
A
m∠V = 30°, m∠U = 60°, m∠W = 90°
B
m∠V = 90°, m∠U = 60°, m∠W = 30°
C
m∠V = 30°, m∠U = 90°, m∠W = 60°
D
m∠V = 60°, m∠U = 90°, m∠W = 30°
17

Trigonometric area formula: Area =

Question illustration
A
70.5 square units
B
111.3 square units
C
185.4 square units
D
222.5 square units
19

The equation can be used to find the length of .

Question illustration
A
19.3 in.
B
21.3 in.
C
23.5 in.
D
68.0 in.

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