Unit Test — Unit test Answers

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Which is the most efficient first step to solve for x in the equation ?

Question illustration
A
Add 3.7x to both sides of the equation.
B
Add 4.3x to both sides of the equation.
C
Subtract 18 from both sides of the equation.
D
Subtract 34 from both sides of the equation.
43

Which equation is equivalent to ?

Question illustration
A
Negative StartFraction 5 Over 6 EndFraction = one-fourth x + one-fourth
Option A
B
Two-thirds x = negative StartFraction 5 Over 12 EndFraction x minus StartFraction 7 Over 12 EndFraction
Option B
C
One-fourth x minus StartFraction 5 Over 6 EndFraction = one-fourth
Option C
D
Two-thirds x minus StartFraction 13 Over 12 EndFraction = negative StartFraction 5 Over 12 EndFraction x
Option D
44

Jared wrote an equation for the perimeter of an equilateral triangle as 3x = 20. What does x represent in his equation?

A
perimeter of the triangle
B
area of the triangle
C
side length of the triangle
D
height of the triangle
45

The equation is written in standard form. What is the first step when solving for x?

Question illustration
A
Add 5x to both sides of the equation.
B
Subtract 5x from both sides of the equation.
C
Add 10y to both sides of the equation.
D
Subtract 10y from both sides of the equation.
47

Jorge solves the equation using the steps below. Step 1: Step 2: Step 3: Step 4: Step 5: Jorge verifies his solution by substituting into the original equation for x. He determines that his solution is incorrect. Which best describes Jorge’s error?

Question illustration
A
Jorge distributed incorrectly.
B
Jorge incorrectly combined like terms.
C
Jorge incorrectly applied the addition and subtraction properties of equality.
D
Jorge incorrectly applied the multiplication and division properties of equality.
48

Horatio is solving the equation . Which equations represent possible ways to begin solving for x? Check all that apply.

Question illustration
A
Two-fifths x = StartFraction 7 Over 20 EndFraction x + one-fourth
Option A
B
Two-fifths x = StartFraction 7 Over 20 EndFraction x + five-fourths
Option B
C
Negative three-fourths = negative StartFraction 1 Over 20 EndFraction x minus one-half
Option C
D
Negative three-fourths = three-fourths x minus one-half
Option D
E
Negative three-fourths + StartFraction 1 Over 20 EndFraction x = negative one-half
Option E
51

A regular hexagon and a rectangle have the same perimeter, P. A side of the hexagon is 4 less than the length, l, of the rectangle. The width of the rectangle, w, is 2 less than the length of the rectangle. What is the perimeter of the hexagon?

Question illustration
Answer not available
55

Consider the solution to the linear equation. Which describes the inverse operations used after the distributive property?

Question illustration
A
addition then division
B
subtraction then division
C
multiplication then subtraction
D
division then addition
56

Three more than twice the sum of a number and half the number equals 105. Which equation models this relationship?

A
2 (x + one-half x) + 3 = 105
B
2 x + one-half x + 3 = 105
C
2 x + 3 = one-half x + 105
D
2 (x + 3) = one-half x + 105
58

Maricella solves for x in the equation . She begins by adding –4 + 4 on the left side of the equation and 1 + 1 on the right side of the equation. Which best explains why Maricella’s strategy is incorrect?

Question illustration
A
The multiplication that takes place while distributing comes before addition and subtraction in order of operations.
B
In order to combine like terms on one side of the equation, the inverse operation must be used.
C
When the problem is worked in the correct order, the numbers that Maricella added are not actually like terms.
D
Maricella did not combine all three constants on both sides of the equation; she combined only two.
59

Erin is a dog groomer. She charges a $6.00 base fee plus an extra $0.50 per pound. If x represents the weight of the dog in pounds, which equation models her income for each dog groomed?

A
Income = 0.5 x + 6
Option A
B
Income = 5 x + 6
Option B
C
Income = 6 x + 0.5
Option C
D
Income = 6 x + 5
Option D
60

Solve for k.8k + 2m = 3m + k

A
k = 70m
B
k = 7m
C
k =
Option C
D
k =
Option D

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