Becca graphs the equations y = –3(x – 1) and y = x – 5 to solve the equation –3(x – 1) = x – 5. Her graph is shown below.What are the solution(s) of –3(x – 1) = x – 5?

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Revolt · Accepted Answer

2

Solving One-Variable Equations with Systems — Unit test

Becca graphs the equations y = –3(x – 1) and y = x – 5 to solve the equation –3(x – 1) = x – 5. Her graph is shown below.What are the solution(s) of –3(x – 1) = x – 5?

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