AnswersFL-1200700-Mathematics for College Algebra MISRadical Equations and Extraneous Roots

Radical Equations and Extraneous Roots — Unit test Answers

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41
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What is the following sum?

Question illustration
A
7 x (RootIndex 6 StartRoot x squared y EndRoot)
Option A
B
7 x squared (RootIndex 6 StartRoot x y squared EndRoot)
Option B
C
7 x squared (RootIndex 3 StartRoot x y squared EndRoot)
Option C
D
7 x (RootIndex 3 StartRoot x squared y EndRoot)
Option D
42
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Which expression is equivalent to ?

Question illustration
A
216
B
1,728
C
RootIndex 3 StartRoot 12 EndRoot
Option C
D
RootIndex 3 StartRoot 72 EndRoot
Option D
43

Which expression is equivalent to ?

Question illustration
A
StartFraction RootIndex 4 StartRoot 200 EndRoot Over 2 EndFraction
Option A
B
StartFraction RootIndex 4 StartRoot 20 EndRoot Over 2 EndFraction
Option B
C
StartFraction 2 StartRoot 5 EndRoot Over 5 EndFraction
Option C
D
StartFraction 100 Over 8 EndFraction
Option D
44

The formula gives the length of the side, s, of a cube with a surface area, SA. How much longer is the side of a cube with a surface area of 1,200 square inches than a cube with the surface area of 768 square inches?

Question illustration
A
in.
Option A
B
in.
Option B
C
in.
Option C
D
in.
Option D
45

Which function has the domain ?

Question illustration
A
y = StartRoot x + 11 EndRoot + 5
Option A
B
y = StartRoot x minus 11 EndRoot + 5
Option B
C
y = StartRoot x + 5 EndRoot minus 11
Option C
D
y = StartRoot x + 5 EndRoot + 11
Option D
46

What is the following product?

Question illustration
A
2 StartRoot 10 EndRoot
Option A
B
3 StartRoot 10 EndRoot
Option B
C
4 StartRoot 10 EndRoot
Option C
D
10 StartRoot 3 EndRoot
Option D
47

Kaylib’s eye-level height is 48 ft above sea level, and Addison’s eye-level height is ft above sea level. How much farther can Addison see to the horizon? Use the formula , with d being the distance they can see in miles and h being their eye-level height in feet.

Question illustration
A
mi
Option A
B
mi
Option B
C
mi
Option C
D
mi
Option D
48

Which expression is equivalent to ?

Question illustration
A
StartFraction RootIndex 12 StartRoot 27 EndRoot Over 2 EndFraction
Option A
B
StartFraction RootIndex 4 StartRoot 24 EndRoot Over 2 EndFraction
Option B
C
StartFraction RootIndex 12 StartRoot 55296 EndRoot Over 2 EndFraction
Option C
D
StartFraction RootIndex 12 StartRoot 177147 EndRoot Over 3 EndFraction
Option D
49

What is the simplified form of the following expression?

Question illustration
A
6 StartRoot 2 EndRoot
Option A
B
18 StartRoot 2 EndRoot
Option B
C
30 StartRoot 2 EndRoot
Option C
D
36 StartRoot 2 EndRoot
Option D
50

What is the following quotient?

Question illustration
A
StartFraction 9 StartRoot 7 EndRoot + StartRoot 14 EndRoot Over negative 3 EndFraction
Option A
B
StartFraction 36 minus 9 StartRoot 7 EndRoot + 4 StartRoot 2 EndRoot minus StartRoot 14 EndRoot EndFraction
Option B
C
StartFraction 36 + 9 StartRoot 7 EndRoot + 4 StartRoot 2 EndRoot + StartRoot 14 EndRoot Over 9 EndFraction
Option C
D
StartFraction 79 Over 9 EndFraction
Option D
51

What is the following product? Assume

Question illustration
A
80 x Superscript 4 Baseline + 8 x Superscript 4 Baseline StartRoot 30 x EndRoot + 24 x Superscript 4
Option A
B
80 x Superscript 6 Baseline + 8 x Superscript 5 Baseline + 8 x Superscript 5 Baseline StartRoot 30 EndRoot + 24 x Superscript 4
Option B
C
104 x Superscript 4
Option C
D
104 x Superscript 4 + 16 x Superscript 4 Baseline StartRoot 30 EndRoot
Option D
52

Which function is undefined for x = 0?

A
y = RootIndex 3 StartRoot x minus 2 EndRoot
Option A
B
y = StartRoot x minus 2 EndRoot
Option B
C
y = RootIndex 3 StartRoot x + 2 EndRoot
Option C
D
y = StartRoot x + 2 EndRoot
Option D
53

The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula . If Saturn’s orbital period is 29.5 years, what is its distance from the sun?

Question illustration
A
9.5 AU
B
19.7 AU
C
44.3 AU
D
160.2 AU

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