AnswersSS Integrated Math IIB 2026Performance Task: Applying Probability Concepts

Performance Task: Applying Probability Concepts — Unit test Answers

23 verified answers
1
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The difference between an observational study and an experiment is that

A
in an observational study, only one group is studied, and in an experiment, two groups are studied.
B
in an observational study, the researchers do not control treatment, and in an experiment, they do.
C
in an experiment, cause-and-effect is analyzed, and in an observational study, it is not.
D
in an experiment, one group is studied over a short period of time, and in an observational study, the group is studied over a longer period of time.
2
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The mean of a set of credit scores is and . Which statement must be true about z694?

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A
z694 is within 1 standard deviation of the mean.
B
z694 is between 1 and 2 standard deviations of the mean.
C
z694 is between 2 and 3 standard deviations of the mean.
D
z694 is more than 3 standard deviations of the mean.
3

The graph below is used by company 2 to show the average monthly electric cost based on the electricity provider.How could the graph be redrawn so that the difference in monthly electric cost does not appear as great?

Question illustration
A
The scale on the y-axis could be changed to 0–150.
B
The scale on the y-axis could be changed to 100–120.
C
The interval on the y-axis could be changed to count by 1s.
D
The interval on the y-axis could be changed to count by 20s.
4

The mean game scores and standard deviations of four seasons of a football team are given below.SeasonMeanStandard Deviation2005193.52006212.82007121.0200894.0Which statement must be true?

A
The game scores of season 2006 have a greater spread than the game scores of season 2008.
B
The game scores of season 2007 have a greater spread than the game scores of season 2005.
C
The game scores of season 2006 have a greater spread than the game scores of season 2005.
D
The game scores of season 2005 have a greater spread than the game scores of season 2006.
7

The mean test scores with standard deviations of four English classes are given below.ClassMeanStandard DeviationMrs. Jones891.9Mrs. Rijo821.4Mr. Phan733.4Mrs. Scott906.1Which statement is most likely to be true?

A
The scores of Mrs. Scott’s class are the closest to the class mean.
B
The scores of Mr. Phan’s class are the closest to the class mean.
C
The scores of Mrs. Jones’s class are the closest to the class mean.
D
The scores of Mrs. Rijo’s class are the closest to the class mean.
8

A convenience sample differs from a voluntary sample in that

A
a convenience sample is structured based on accessibility to the researcher, and a voluntary sample is based on participant interest.
B
convenience samples survey each participant once, and voluntary samples survey each participant numerous times.
C
convenience sampling is a method of random sampling, and a voluntary sample is not.
D
convenience sampling is not a probability-based method, and voluntary sampling is.
9

The histogram below represents the number of points Mandy scored per game. The graph makes the data appear symmetric when it is actually skewed. How can the graph be adjusted to show the skew?

Question illustration
A
The intervals on the x-axis can be changed to be continuous and consistent.
B
The interval on the y-axis can be changed to show only the relevant numbers, 3 and 5.
C
The scale on the x-axis can be increased to show the interval 25–29.
D
The scale on the y-axis can be decreased to show only the numbers 0–5.
10

Emi computes the mean and variance for the population data set 87, 46, 90, 78, and 89. She finds the mean is 78. Her steps for finding the variance are shown below.What is the first error she made in computing the variance?

Question illustration
A
Emi failed to find the difference of 89 - 78 correctly.
B
Emi divided by N - 1 instead of N.
C
Emi evaluated (46 - 78)2 as -(32)2.
D
Emi forgot to take the square root of -135.6.
11

The stem-and-leaf plot below shows the number of pages each student in a class read the previous evening.Which statement is true about the data set?

Question illustration
A
Its median is greater than its mode.
B
It has a range of 52 pages.
C
The value of the first quartile is 13.
D
The data is symmetric.
13

Yuri computes the mean and standard deviation for the sample data set 12, 14, 9, and 21. He finds the mean is 14. His steps for finding the standard deviation are below.What is the first error he made in computing the standard deviation?

Question illustration
A
Yuri failed to find the difference between each data point and the mean.
B
Yuri divided by n instead of n -1.
C
Yuri did not subtract 9 - 14 correctly.
D
Yuri failed to square -2 correctly.
14

The box-and-whisker plot below shows the age distribution of people at a family reunion.The stem-and-leaf plot below shows the same data.Which of the following best explains why one graph appears skewed and one graph appears symmetrical?

Question illustration
A
The scale of the box-and-whisker plot does not start at zero.
B
The interval of the box-and-whisker plot is too large.
C
The interval of the stem-and-leaf plot is not consistent.
D
The scale of the stem-and-leaf plot is too small for the set of data.
15

The mean ages with standard deviations of four swim teams at a swim club are given below.TeamMeanStandard DeviationStars164.1Dolphins181.5Giants140.3Mackerels152.3Which statement is most likely to be true?

A
The ages of the Mackerels are the most dispersed from the team’s mean.
B
The ages of the Stars are the most dispersed from the team’s mean.
C
The ages of the Dolphins are the most dispersed from the team’s mean.
D
The ages of the Giants are the most dispersed from the team’s mean.
17

The monthly mean salaries and standard deviations of four college students are given below.StudentMeanStandard DeviationClarissa$34512.53Abi$5988.99Kaila$81215.29Shenika$2087.67Which statement must be true?

A
The monthly salary of Shenika is less spread out than the monthly salary of Clarissa.
B
The monthly salary of Kaila is less spread out than the monthly salary of Abi.
C
The monthly salary of Abi is less spread out than the monthly salary of Shenika.
D
The monthly salary of Clarissa is less spread out than the monthly salary of Abi.
19

Charles owns a catering business. The amount his 10 most recent clients spent is shown in the histogram below. Why is the graph misleading?

Question illustration
A
The x-axis scale shows the data is more clustered than it actually is.
B
The y-axis scale shows the data is more skewed than it actually is.
C
The scales are different on the x-axis and the y-axis.
D
The data is not distributed equally across the x-axis intervals.

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