AnswersLJISD-TX-Algebra II-4th 6WKSUnit Test

Unit Test — Unit test Answers

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24
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Which statement is true about the discontinuities of the function f(x)?

Question illustration
A
There are asymptotes at and .
Option A
B
There are holes at and .
Option B
C
There are asymptotes at and .
Option C
D
There are holes at and .
Option D
25
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What is the product?

Question illustration
A
StartFraction 4 n Over n + 1 EndFraction
Option A
B
StartFraction n Over n + 1 EndFraction
Option B
C
StartFraction 1 Over n + 1 EndFraction
Option C
D
StartFraction 4 Over n + 1 EndFraction
Option D
26

Identify the graph of the rational function with an x-intercept at (–4, 0) and (4, 0), a vertical asymptote at x = 2, and an oblique asymptote at y = x + 2.

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
27

Which graph represents the function ?

Question illustration
A
On a coordinate plane, a hyperbola and parabola are shown. The hyperbola has a curve in quadrants 1 and 2. The parabola opens down and has a vertex at (0, 0).
Option A
B
On a coordinate plane, a hyperbola and a cubic functions are shown. They hyperbola has curves in quadrants 1 and 3, and the cubic function goes through (0, 0).
Option B
C
On a coordinate plane, a hyperbola is shown. One curve is in quadrant 1 and the other curves goes through quadrants 2 and 4.
Option C
D
On a coordinate plane, a hyperbola is shown. Both curves open downward in quadrants 3 and 4.
Option D
28

How can Ari simplify the following expression?

Question illustration
A
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerator by the reciprocal of the denominator.
B
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerators and multiply the denominators.
C
Divide the numerator and the denominator by a – 3. Then divide the numerator by the denominator.
D
Divide the numerator and the denominator by a – 3. Then simplify the numerator and simplify the denominator.
29

Which expression is equivalent to the expression below?

Question illustration
A
StartFraction 1 Over (m + 4) (m + 3) EndFraction
Option A
B
StartFraction 1 Over (m minus 4) (m minus 3) EndFraction
Option B
C
StartFraction m minus 4 Over m minus 3 EndFraction
Option C
D
StartFraction m + 3 Over m + 4 EndFraction
Option D
30

Which graph represents the function ?

Question illustration
A
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.
Option A
B
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.25.
Option B
C
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.
Option C
D
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.25.
Option D
31

Which expression is equivalent to ?

Question illustration
A
StartFraction m minus 4 Over (m + 4) (m + 2) EndFraction
Option A
B
StartFraction (m + 4) (m + 2) Over m minus 4 EndFraction
Option B
C
StartFraction (m minus 4) (m + 2) Over m + 4 EndFraction
Option C
D
StartFraction m + 4 Over (m minus 4) (m + 2) EndFraction
Option D
32

How does the graph of compare to the graph of the parent function ?

Question illustration
A
g(x) is shifted 5 units left and 2 units up from f(x).
B
g(x) is shifted 5 units right and 2 units up from f(x).
C
g(x) is shifted 5 units left and 2 units down from f(x).
D
g(x) is shifted 5 units right and 2 units down from f(x).
33

What is the quotient?

Question illustration
A
StartFraction negative (a minus 3) squared Over 147 EndFraction
Option A
B
StartFraction (a minus 3) squared Over 147 EndFraction
Option B
C
3
D
–3
34

Which statement describes the behavior of the function ?

Question illustration
A
The graph approaches –3 as x approaches infinity.
B
The graph approaches 0 as x approaches infinity.
C
The graph approaches 3 as x approaches infinity.
D
The graph approaches 4 as x approaches infinity.
35

Megan borrowed $50,000 at 5% simple interest for 6 years. Joseph borrowed $60,000 at 4% simple interest for 8 years. The formula can be used to calculate the monthly payment, m, where P is the principle amount borrowed, r is the rate expressed as a decimal, and t is the amount of time for the loan, in years. Who will have a greater monthly payment, and by how much?

Question illustration
A
Megan will pay approximately $8 dollars more per month.
B
Megan will pay approximately $78 dollars more per month
C
Joseph will pay approximately $8 dollars more per month.
D
Joseph will pay approximately $78 dollars more per month.
36

Where are the vertical asymptotes for the following function located?

Question illustration
A
x = –4 and x = 6
B
x = –4 and x = 7
C
x = 4 and x = –6
D
x = 6 and x = 7
37

The increase in a person’s body temperature T(t), above 98.6ºF, can be modeled by the function , where t represents time elapsed. What is the meaning of the horizontal asymptote for this function?

Question illustration
A
The horizontal asymptote of y = 0 means that the person’s temperature will approach 98.6ºF as time elapses.
B
The horizontal asymptote of y = 0 means that the person’s temperature will approach 0ºF as time elapses.
C
The horizontal asymptote of y = 4 means that the person’s temperature will approach 102.6ºF as time elapses.
D
The horizontal asymptote of y = 4 means that the person’s temperature will approach 4ºF as time elapses.
38

What is the difference?

Question illustration
A
StartFraction 2 (x + 6) Over (x + 4) (x minus 4) EndFraction
Option A
B
StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction
Option B
C
StartFraction x minus 3 Over (x + 5) (x minus 4) EndFraction
Option C
D
StartFraction negative 2 (x minus 6) Over (x + 4) (x minus 4) EndFraction
Option D
39

Where are the vertical asymptotes for the following function located?

Question illustration
A
x = –4 and x = 6
B
x = –4 and x = 7
C
x = 4 and x = –6
D
x = 6 and x = 7
40

Mr. Knotts found the difference of the following expression. Which statement is true about Mr. Knotts’s work? Step 1: Step 2: Step 3: Step 4:

Question illustration
A
In step 1, he did not correctly factor the denominator.
B
In step 2, he did not use the correct common denominator.
C
In step 3, he did not distribute the negative sign when he subtracted.
D
In step 4, he did not correctly subtract the numerator.
41

Which statement describes the vertical asymptotes of the graph of ?

Question illustration
A
The graph has no vertical asymptote.
B
The graph has a vertical asymptote at x = 8 only.
C
The graph has a vertical asymptote at x = –8 only.
D
The graph has vertical asymptotes at both x = 8 and x = –8.
42

Max can mow a lawn in 45 minutes. Jan takes twice as long to mow the same lawn. If they work together, the situation can be modeled by the following equation, where t is the number of minutes it would take to mow the lawn together.How long will it take Maxine and Jan to mow the lawn together?

Question illustration
A
30.0 minutes
B
45.0 minutes
C
67.5 minutes
D
135.0 minutes
43

Which graph represents the function ?

Question illustration
A
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.
Option A
B
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.25.
Option B
C
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.
Option C
D
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.25.
Option D

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