AnswersMHS - Algebra 1 - S1 - CRUnit Test

Unit Test — Unit test Answers

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The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = (x – 8). What is the slope-intercept form of the equation for this line?

Question illustration
A
y = x – 12
Option A
B
y = x – 4
Option B
C
y = x + 2
Option C
D
y = x + 6
Option D
22
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The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?

A
(7, 3)
B
(0, 7)
C
(7, 0)
D
(3, 7)
23

The final cost of a sale item is determined by multiplying the price on the tag by 75%. Which best describes the function that represents the situation?

Question illustration
A
It is linear because the ratio of the change in the final cost compared to the rate of change in the price tag is constant.
B
It is linear because the function is continuous.
C
It is nonlinear because the final cost is determined by multiplying each price tag by 0.75.
D
It is nonlinear because the price tag and final cost columns do not have the same common difference.
24

Which relationship has a zero slope?

Question illustration
A
Option
B
Option
C
Option
D
Option
25

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, then m=. What is the value of b?

Question illustration
A
−6
B
−5
C
5
D
6

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