AnswersTPS-202627-MTH-Geometry 1A-CRUnit Test

Unit Test — Unit test Answers

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41
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The side lengths of triangle ABC are 3, 4, and 5. Which set of ordered pairs form a triangle that is congruent to triangle ABC?

A
(−3,1),(−3,5),(0,5)
B
(1,−2),(1,3),(4,3)
C
(6,−3),(1,−3),(6,1)
D
(1,3),(1,4),(5,1)
42
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On a coordinate plane, line A B goes through (negative 2, 4) and (2, negative 8). Point C is at (6, 4).

Question illustration
A
(–6, 0)
B
(0, –6)
C
(0, 2)
D
(2, 0)
43

On a coordinate plane, line K L goes through (negative 6, 8) and (6, 0). Point M is at (negative 4, negative 2).

Question illustration
A
(–10, 0)
B
(–6, 2)
C
(0, –6)
D
(8, –10)
44

Triangle MNO is congruent to right triangle RST with a right angle at vertex R. If the slope of RS is, what must be true?

Question illustration
A
The slope of TR is 5.
B
The slope of OM is 5.
C
The slope of MN is
Option C
D
The slope of NO is
Option D
45

On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (negative 6, negative 5) and (0, 0). Line J K goes through (negative 6, 1) and (0, negative 4). Line P Q goes through (negative 5, 4) and (0, negative 2).

Question illustration
A
line JK
B
line LM
C
line NO
D
line PQ
46

On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, negative 2), and point K is at (negative 2, negative 3).

Question illustration
A
(1,−1)
B
(1,1)
C
(1,0)
D
(0,1)
47

On a coordinate plane, line M N goes through (negative 4, 0) and (4, 2). Point P is at (2, negative 4).

Question illustration
A
(0, 1)
B
(0, 4)
C
(1, 0)
D
(4, 0)
48

Question text not available

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
49

Question text not available

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
50

On a coordinate plane, 4 lines are shown. Line A B goes through (negative 4, 3) and (4, 3). Line C D goes through (negative 3, 0) and (3, 2). Line F G goes through (negative 3, negative 1) and (3, negative 3). Line H J goes through (negative 1, negative 4) and (1, 2).

Question illustration
A
line AB
B
line CD
C
line FG
D
line HJ
51

Question text not available

Question illustration
A
AB = 2AD
B
AD = 2AB
C
BC = 2DE
D
DE = 2BC
52

On a coordinate plane, 4 lines are shown. Line A B goes through (negative 4, negative 2) and (4, 2). Line C D goes through (negative 4, 0) and (4, negative 4). Line F G goes through (negative 3, negative 3) and (0, 3). Line H J goes through (negative 1, 3) and (1, negative 1).

Question illustration
A
line AB
B
line CD
C
line FG
D
line HJ
53

On a coordinate plane, 2 lines are shown. Line M N goes through (negative 4, 8) and (negative 4, negative 6). Line K L goes through (negative 8, 2) and (6, 2).

Question illustration
A
The lines intersect at point K.
B
The lines are parallel.
C
The lines are perpendicular.
D
The lines do not have slopes.
54

Line WV is perpendicular to both line RS and line TU.

Question illustration
A
Line TU is parallel to line RS.
B
Line TU is perpendicular to line RS.
C
Line TU has no slope.
D
Line TU has a slope of –5.
55

Triangle ABC was dilated using the rule .

Question illustration
A
10 units
B
12 units
C
16 units
D
20 units
56

Triangle R Q S is cut by line segment T V. Line segment T V goes from side Q R to side R S. The length of R V is x + 10, the length of V S is x, the length of R T is x + 4, and the length of T Q is x minus 3.

Question illustration
A
3
B
8
C
10
D
11
57

Consider △RST and △RYX.

Question illustration
A
StartFraction R Y Over Y S EndFraction = StartFraction R X Over X T EndFraction = StartFraction X Y Over T S EndFraction
Option A
B
StartFraction R Y Over R S EndFraction = StartFraction R X Over R T EndFraction = StartFraction X Y Over T S EndFraction
Option B
C
StartFraction R Y Over R S EndFraction = StartFraction R X Over R T EndFraction = StartFraction R S Over R Y EndFraction
Option C
D
StartFraction R Y Over R X EndFraction = StartFraction R S Over R T EndFraction = StartFraction X Y Over T S EndFraction
Option D
58

Which best explains why all equilateral triangles are similar?

A
All equilateral triangles can be mapped onto each other using dilations.
B
All equilateral triangles can be mapped onto each other using rigid transformations.
C
All equilateral triangles can be mapped onto each other using combinations of dilations and rigid transformations.
D
All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
59

Parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'.

Question illustration
A
One-eighth
Option A
B
One-fourth
Option B
C
4
D
8
60

Triangles R S T and V U T are connected at point T. Angles R S T and V U T are right angles. The length of side R S is 12 and the length of side S T is 16. The length of side T U is 8 and the length of U V is 6.

Question illustration
A
StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U
Option A
B
StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction = StartFraction R T Over V T EndFraction
Option B
C
StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction and angle S is-congruent-to angle U
Option C
D
StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction = StartFraction R T Over V T EndFraction
Option D

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