Solving One-Variable Inequalities — Unit test Answers

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What is the value of x in the equation ?

Question illustration
A
StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3.
Option A
B
StartFraction one-half EndFraction left-parenthesis n minus 4 right-parenthesis minus 3 equals 3 minus left-parenthesis 2 n plus 3 right-parenthesis.
Option B
C
2
D
13
3

Lily begins solving the equation 4(x – 1) – x = 3(x + 5) – 11. Her work is shown below.4(x – 1) – x = 3(x + 5) – 11 4x – 4 – x = 3x + 15 – 113x – 4 = 3x + 4

A
The equation has one solution: x = 0.
B
The equation has one solution: x = 8.
C
The equation has no solution.
D
The equation has infinite solutions.
5

Solve the equation.–9x + 1 = –x + 17

A
x = –8
B
x = –2
C
x = 2
D
x = 8
13

Which number line represents the solutions to –2|x| = –6?

A
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 6 and one at negative 2.
Option A
B
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 8 and one at negative 4.
Option B
C
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 4 and one at 4.
Option C
D
A number line from negative 8 to 8 in increments of 1. Two points, one at negative 3 and one at 3.
Option D
20

Johan found that the equation –2|8 – x| – 6 = –12 had two possible solutions: x = 5 and x = –11. Which explains whether his solutions are correct?

A
He is correct because both solutions satisfy the equation.
B
He is not correct because he made a sign error.
C
He is not correct because there are no solutions.
D
He is not correct because there is only one solution: x = 5.

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