AnswersCommon Core Algebra I A-ICSolving One-Variable Inequalities

Solving One-Variable Inequalities — Unit test Answers

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What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?

A
–12 – 20x ≤ –6x + 9
B
–12 – 20x ≥ –6x + 9
C
–12 + 20x ≤ –6x + 9
D
–12 + 20x ≥ –6x + 9
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A
four times
B
two times
C
less than
D
the same as
44

Fiona solved the equation shown. – (6x – 3) = –

Question illustration
A
Simplify by combining like terms.
B
Simplify by using addition property of equality.
C
Simplify by using the multiplication property of equality.
D
Simplify by using the division property of equality.
45

Solve the equation.y + 3 = –y + 9

A
y = 1
B
y = 3
C
y = 6
D
y = 9
46

Deepak wrote out the steps to his solution of the equation – 3x – 5 + 4x = –. Which step has an incorrect instruction?

Question illustration
A
Step 1
B
Step 2
C
Step 3
D
Step 4
47

The heat in the house is set to keep the minimum and maximum temperatures (in degrees Fahrenheit) according to the equation |x – 72.5| = 4. What are the minimum and maximum temperatures in the house?

A
72.5°F and 76.5°F
B
68.5°F and 76.5°F
C
70.5°F and 74.5°F
D
72.5°F and 74.5°F
48

Lily begins solving the equation 4(x – 1) – x = 3(x + 5) – 11. Her work is shown below.4(x – 1) – x = 3(x + 5) – 11 4x – 4 – x = 3x + 15 – 113x – 4 = 3x + 4

A
The equation has one solution: x = 0.
B
The equation has one solution: x = 8.
C
The equation has no solution.
D
The equation has infinite solutions.
49

What is the value of x in the equation ?

Question illustration
A
StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3.
Option A
B
StartFraction one-half EndFraction left-parenthesis n minus 4 right-parenthesis minus 3 equals 3 minus left-parenthesis 2 n plus 3 right-parenthesis.
Option B
C
2
D
13

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