Unit Test — Unit test Answers

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A convenience sample differs from a voluntary sample in that

A
a convenience sample is structured based on accessibility to the researcher, and a voluntary sample is based on participant interest.
B
convenience samples survey each participant once, and voluntary samples survey each participant numerous times.
C
convenience sampling is a method of random sampling, and a voluntary sample is not.
D
convenience sampling is not a probability-based method, and voluntary sampling is.
3

The mean of a set of credit scores is and . Which statement must be true about z694?

Question illustration
A
z694 is within 1 standard deviation of the mean.
B
z694 is between 1 and 2 standard deviations of the mean.
C
z694 is between 2 and 3 standard deviations of the mean.
D
z694 is more than 3 standard deviations of the mean.
4

The mean game scores and standard deviations of four seasons of a football team are given below.SeasonMeanStandard Deviation2005193.52006212.82007121.0200894.0Which statement must be true?

A
The game scores of season 2006 have a greater spread than the game scores of season 2008.
B
The game scores of season 2007 have a greater spread than the game scores of season 2005.
C
The game scores of season 2006 have a greater spread than the game scores of season 2005.
D
The game scores of season 2005 have a greater spread than the game scores of season 2006.
5

Which normal distribution has the greatest standard deviation?

A
A normal distribution is shown. The curve peaks at 96 and hits the axis at 75 and 115.
Option A
B
A normal distribution is shown. The curve peaks at 60 and hits the axis at 48 and 72.
Option B
C
A normal distribution is shown. The curve peaks at 16 and there is area under the curve at all points.
Option C
D
A normal distribution is shown. The curve peaks at 32 and hits the axis at 28 and 38.
Option D
6

The histogram below represents the number of points Mandy scored per game. The graph makes the data appear symmetric when it is actually skewed. How can the graph be adjusted to show the skew?

Question illustration
A
The intervals on the x-axis can be changed to be continuous and consistent.
B
The interval on the y-axis can be changed to show only the relevant numbers, 3 and 5.
C
The scale on the x-axis can be increased to show the interval 25–29.
D
The scale on the y-axis can be decreased to show only the numbers 0–5.
9

When making a statistical inference about the mean of a normally distributed population based on a sample drawn from that population, which of the following statements is correct, all else being equal?

A
The 68% confidence interval is wider than the 90% confidence interval.
B
The 90% confidence interval is narrower than the 95% confidence interval.
C
The 90% confidence interval is wider than the 99% confidence interval.
D
The 99% confidence interval is narrower than the 68% confidence interval.
11

A local weather enthusiast wants to see if the last five summers have been warmer than normal for Eloy, Arizona. From the National Oceanic and Atmospheric Administration (NOAA), he knows the 30-year average for July was 90° with a standard deviation of 2.1°. The last five summers recorded have an average of 93.5°. If he uses a = 5%, which of the following would be valid based on the data he has gathered?

A
He can conclude that the summers have been warmer than the 30-year average.
B
He can conclude that the summers will continue to be warmer for the next 10 years.
C
He does not have enough information to make a decision.
D
The average for the last five years fits with the 30-year average.
12

Glenda checks the computer monitors made at her company for defects. It has been shown that 0.5% of the monitors are defective. She decides to check several monitors and record if they are defective. Which of the following will make this process into a binomial experiment?

A
Glenda checks the monitors until she has 300 defective monitors.
B
Glenda checks 300 monitors and records the number that are defective until she gets greater than 0.5% defective monitors.
C
Glenda checks the monitors until she has 300 non-defective monitors.
D
Glenda chooses to check 300 monitors.
14

For a standard normal distribution, which of the following expressions must always be equal to 1?

A
P (z less-than-or-equal-to a) minus P (negative a less-than-or-equal-to z less-than-or-equal-to z) minus P (z greater-than-or-equal-to a)
Option A
B
P (z less-than-or-equal-to a) minus P (negative a less-than-or-equal-to z less-than-or-equal-to z) + P (z greater-than-or-equal-to a)
Option B
C
P (z less-than-or-equal-to a) + P (negative a less-than-or-equal-to z less-than-or-equal-to z) minus P (z greater-than-or-equal-to a)
Option C
D
P (z less-than-or-equal-to a) + P (negative a less-than-or-equal-to z less-than-or-equal-to z) + P (z greater-than-or-equal-to a)
Option D
17

Two students have devised a dice game named “Sums” for their statistics class. The game consists of choosing to play odds or evens. Probabilities for “Sums”Roll23456789101112P(roll)Each person takes turns rolling two dice. If the sum is odd, the person playing odds gets points equal to the sum of the roll. If the sum is even, the person playing evens gets points equal to the sum of the roll. Note that the points earned is independent of who is rolling the dice.If Jessica is challenged to a game of Sums, which statement below is accurate in every aspect in guiding her to the correct choice of choosing to play odds or evens?

Question illustration
A
E(evens) will be more because there are more even numbers that result from rolling two dice. Therefore, Jessica should play evens.
B
E(odds) will be more because the probability for each odd number being rolled is greater. Therefore, Jessica should play odds.
C
E(evens) will be more because the value of the even numbers on the dice are more. Therefore, Jessica should play evens.
D
E(evens) = E(odds) because the different probabilities and values end up balancing out, creating a fair game. Therefore, Jessica may choose whichever she likes.
20

Which of the following is a valid probability distribution?

A
Probability distribution A is shown. The probabilities of 1, 2, 3, 4, 5 and 6 are all 0.2.
Option A
B
Probability distribution B is shown. The probability of 1 is 0.1; 2 is 0.2; 3 is 0.3; 4 is 0.3; 5 is 0.2; 6 is 0.1.
Option B
C
Probability distribution C is shown. The probability of 1 is 0.1; 2 is 0.2; 3 is 0.4; 5 is 0.1; 6 is 0.1.
Option C
D
Probability distribution D is shown. The probability of 1 is 0.2; 2 is 0.1; 3 is 0.1; 4 is 0.5; 5 is 0.1.
Option D

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