AnswersINMT3 Integrated Math 3 Sem 1 26-27Modeling with Quadratic Equations

Modeling with Quadratic Equations — Unit test Answers

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1
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Which expression is equivalent to ?

Question illustration
A
StartFraction m minus 4 Over (m + 4) (m + 2) EndFraction
Option A
B
StartFraction (m + 4) (m + 2) Over m minus 4 EndFraction
Option B
C
StartFraction (m minus 4) (m + 2) Over m + 4 EndFraction
Option C
D
StartFraction m + 4 Over (m minus 4) (m + 2) EndFraction
Option D
2
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Which expression is equivalent to the expression below?

Question illustration
A
StartFraction 1 Over (m + 4) (m + 3) EndFraction
Option A
B
StartFraction 1 Over (m minus 4) (m minus 3) EndFraction
Option B
C
StartFraction m minus 4 Over m minus 3 EndFraction
Option C
D
StartFraction m + 3 Over m + 4 EndFraction
Option D
4

Which statement is true about the discontinuities of the function f(x)?

Question illustration
A
There are asymptotes at and .
B
There are holes at and .
C
There are asymptotes at and .
D
There are holes at and .
5

What is the difference?

Question illustration
A
StartFraction 2 (x + 6) Over (x + 4) (x minus 4) EndFraction
Option A
B
StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction
Option B
C
StartFraction x minus 3 Over (x + 5) (x minus 4) EndFraction
Option C
D
StartFraction negative 2 (x minus 6) Over (x + 4) (x minus 4) EndFraction
Option D
11

Which graph represents the function ?

Question illustration
A
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.
Option A
B
On a coordinate plane, a hyperbola is shown. A curve opens up and to the right in quadrant 1, and another curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0.25.
Option B
C
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.
Option C
D
On a coordinate plane, a hyperbola is shown. A curve opens up and to the left in quadrant 2, and another curve opens down and to the right in quadrant 4. A vertical asymptote is at x = 0.25.
Option D
12

The increase in a person’s body temperature T(t), above 98.6ºF, can be modeled by the function , where t represents time elapsed. What is the meaning of the horizontal asymptote for this function?

Question illustration
A
The horizontal asymptote of y = 0 means that the person’s temperature will approach 98.6ºF as time elapses.
B
The horizontal asymptote of y = 0 means that the person’s temperature will approach 0ºF as time elapses.
C
The horizontal asymptote of y = 4 means that the person’s temperature will approach 102.6ºF as time elapses.
D
The horizontal asymptote of y = 4 means that the person’s temperature will approach 4ºF as time elapses.
14

Which statement describes the vertical asymptotes of the graph of ?

Question illustration
A
The graph has no vertical asymptote.
B
The graph has a vertical asymptote at x = 8 only.
C
The graph has a vertical asymptote at x = –8 only.
D
The graph has vertical asymptotes at both x = 8 and x = –8.
15

What is the solution to the equation ?

Question illustration
A
y = –4 and y = 4
B
y = 0
C
all real numbers
D
no solution
16

The cost of catering a dinner is $11.95 per person plus $25 for delivery and setup. Which statement is true about the graph of the function that represents the average cost per person?

A
The horizontal asymptote y = 0 represents that the cost per person approaches $0 as the number of people increases.
B
The horizontal asymptote y = 11.95 represents that the cost per person approaches $11.95 as the number of people increases.
C
The vertical asymptote x = 0 represents that the cost per person approaches $0 as the number of people increases.
D
The vertical asymptote x = 11.95 represents that the cost per person approaches $11.95 as the number of people increases.
17

How can Ari simplify the following expression?

Question illustration
A
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerator by the reciprocal of the denominator.
B
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do this, multiply the numerators and multiply the denominators.
C
Divide the numerator and the denominator by a – 3. Then divide the numerator by the denominator.
D
Divide the numerator and the denominator by a – 3. Then simplify the numerator and simplify the denominator.
19

Using V = lwh, what is an expression for the volume of the following prism?

Question illustration
A
StartFraction 4 (d minus 2) Over 3 (d minus 3)(d minus 4) EndFraction
Option A
B
StartFraction 4 d minus 8 Over 3 (d minus 4) squared EndFraction
Option B
C
StartFraction 4 Over 3 d minus 12 EndFraction
Option C
D
StartFraction 1 Over 3 d minus 3 EndFraction
Option D
20

What is the product?

Question illustration
A
StartFraction 4 n Over n + 1 EndFraction
Option A
B
StartFraction n Over n + 1 EndFraction
Option B
C
StartFraction 1 Over n + 1 EndFraction
Option C
D
StartFraction 4 Over n + 1 EndFraction
Option D

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