AnswersWINGS PA-26 Algebra II A PottsUnit Test

Unit Test — Unit test Answers

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What is the following product?

Question illustration
A
RootIndex 6 StartRoot 10 EndRoot
Option A
B
RootIndex 6 StartRoot 200 EndRoot
Option B
C
RootIndex 6 StartRoot 500 EndRoot
Option C
D
RootIndex 6 StartRoot 100000 EndRoot
Option D
22
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What is the simplified form of the following expression? Assume .

Question illustration
A
StartFraction 2 (RootIndex 3 StartRoot 6 x squared y squared EndRoot) Over y EndFraction
Option A
B
StartFraction RootIndex 3 StartRoot 12 x squared y EndRoot Over 2 y EndFraction
Option B
C
StartFraction x (RootIndex 3 StartRoot 3 y EndRoot) Over 2 y EndFraction
Option C
D
StartFraction RootIndex 3 StartRoot 6 x squared y squared EndRoot Over 2 y EndFraction
Option D
23

To rationalize the denominator of , you should multiply the expression by which fraction?

Question illustration
A
StartFraction StartRoot 10 EndRoot Over StartRoot 10 EndRoot EndFraction
Option A
B
StartFraction StartRoot 11 EndRoot Over StartRoot 11 EndRoot EndFraction
Option B
C
StartFraction 2 minus StartRoot 10 EndRoot Over 2 minus StartRoot 10 EndRoot EndFraction
Option C
D
StartFraction 3 minus StartRoot 11 EndRoot Over 3 minus StartRoot 11 EndRoot EndFraction
Option D
24

Multiplying by which fraction will produce an equivalent fraction with a rational denominator?

Question illustration
A
StartFraction StartRoot 17 EndRoot minus StartRoot 2 EndRoot Over StartRoot 17 EndRoot minus StartRoot 2 EndRoot EndFraction
Option A
B
StartFraction StartRoot 17 EndRoot + StartRoot 2 EndRoot Over StartRoot 17 EndRoot + StartRoot 2 EndRoot EndFraction
Option B
C
StartFraction StartRoot 2 EndRoot minus StartRoot 17 EndRoot Over StartRoot 2 EndRoot minus StartRoot 17 EndRoot EndFraction
Option C
D
StartFraction StartRoot 15 EndRoot Over StartRoot 15 EndRoot EndFraction
Option D
25

What is the following quotient?

Question illustration
A
StartRoot 13 EndRoot minus 2 StartRoot 11 EndRoot
Option A
B
StartFraction StartRoot 13 EndRoot + StartRoot 11 EndRoot Over 6 EndFraction
Option B
C
StartFraction StartRoot 13 EndRoot + STartRoot 11 EndRoot Over 12 EndFraction
Option C
D
StartRoot 13 EndRoot minus StartRoot 11 EndRoot
Option D

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