AnswersGeometry - Semester 1 PathwaysTriangle Congruence: SSS and HL

Triangle Congruence: SSS and HL — Unit test Answers

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Triangles A B C and Q R S are shown. Sides A B and Q R are congruent. Angles C A B and R Q S are congruent. Angles Q S R and A C B are congruent.

Question illustration
A
a reflection across the line containing AB
B
a rotation about point B
C
a reflection across the line containing CB
D
a rotation about point C
2
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Which pair of triangles can be proven congruent by SAS?

A
2 identical triangles are shown. The triangle is reflected across a line to form the second triangle.
Option A
B
2 identical triangles are shown. The triangle is rotated 90 degrees to form the second triangle.
Option B
C
2 identical triangles are shown. The triangle is reflected across a line and then rotated to form the second triangle.
Option C
D
2 identical triangles are shown. The triangle is rotated up and to the left 90 degrees to form the second triangle.
Option D
3

Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.

Question illustration
A
Yes, they are congruent by either ASA or AAS.
B
Yes, they are both right triangles.
C
No, M is not congruent to NLQ.
Option C
D
No, there are no congruent sides.
4

Triangles J K L and M N R are shown.

Question illustration
A
KL ≅ NR
B
∠L ≅ ∠R
C
∠K ≅ ∠N
D
JK ≅ MN
5

The proof that ΔQPT ≅ ΔQRT is shown.Given: SP ≅ SRProve: ΔQPT ≅ ΔQRT

Question illustration
A
definition of perpendicular bisector
B
definition of congruence
C
reflexive property
D
substitution property
8

Triangles J K L and X Y Z are shown. Angles K J L and Y X Z are right angles. The length of Y X is 10. The length of hypotenuse K L is 10.

Question illustration
A
Yes, if JL ≅ XZ.
B
Yes, if XZ = 10.
C
No, because the hypotenuse of one triangle is equal in length to the leg of the other triangle.
D
No, because the leg of one triangle is equal in length to the leg of the other triangle.
9

The triangles are congruent by the SSS congruence theorem.

Question illustration
A
reflection only
B
rotation only
C
translation, then reflection
D
translation, then rotation
10

Triangles Q R S and A B C are shown. The lengths of sides Q R and A B are 16 centimeters. The lengths of sides R S and B C are 24 centimeters. Angles Q R S and A B C are right angles. Sides Q S and A C are parallel and identical to each other and there is space in between the 2 triangles.

Question illustration
A
No, ΔQRS and ΔABC are congruent but ΔQRS cannot be mapped to ΔABC using a series rigid transformations.
B
No, ΔQRS and ΔABC are not congruent.
C
Yes, ΔQRS can be translated so that R is mapped to B and then rotated so that S is mapped to C.
D
Yes, ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing QS.
12

Triangles H J K and L M N are shown. The triangles have identical side lengths and angle measures. Triangle H J K is slightly lower and to the left of triangle L M N. Triangle H J K is reflected to form triangle L M N.

Question illustration
A
Translate K to N and reflect across the line containing HJ.
B
Translate K to N and reflect across the line containing JK.
C
Translate H to L and reflect across the line containing JK.
D
Translate K to L and reflect across the line containing HJ.
13

Triangles A B C and X Y Z is congruent. Triangle X Y Z is slightly higher and to the right of triangle A B C. Triangle A B C is reflected across a line to form triangle X Y Z.

Question illustration
A
a reflection across the line containing AB
B
a reflection across the line containing AC
C
a rotation about point A
D
a rotation about point B
14

Which of these triangle pairs can be mapped to each other using a single translation?

A
Triangles C E D and C N P are congruent. Triangle C E D is rotated about point C and then reflected across a line to form triangle C N P.
Option A
B
Triangles C N E and C E D are congruent. Triangle C N E is reflected across a line and then rotated slightly to form triangle C E D.
Option B
C
Triangles C E D and M D P are congruent. Triangle M D P is rotated and shifted up to form triangle C E D.
Option C
D
Triangles C E D and M P N are congruent. Triangle C E D is shifted to the right to form triangle M P N.
Option D
15

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K.

Question illustration
A
a reflection across the line containing HK
B
a rotation about point H
C
a reflection across the line containing HJ
D
a rotation about point K
16

Triangles RQS and NTV have the following characteristics:• Right angles at ∠Q and ∠T • RQ ≅ NTCan it be concluded that ΔRQS ≅ ΔNTV by SAS? Why or why not?

A
Yes, one set of corresponding sides and one corresponding angle are congruent.
B
Yes, they are both right triangles.
C
No, it is necessary to know that another set of corresponding sides is congruent.
D
No, it is not possible for the triangles to be congruent.
17

The triangles shown are congruent by the SSS congruence theorem.

Question illustration
A
rotation, then reflection, then translation
B
rotation, then translation, then reflection
C
translation, then reflection, then rotation
D
translation, then rotation, then reflection
18

Which of these triangle pairs can be mapped to each other using a translation and a rotation about point A?

A
Triangles Q R A and K P A are connected at point A. Triangle K P A is rotated to form triangle Q R A.
Option A
B
Triangles Q R A and K P L are shown. Triangle Q R A is reflected and then shifted to the right to form triangle K P L.
Option B
C
Triangles Q R A and K P L are shown. Triangle Q R A is reflected and then shifted to the right to form triangle K P L.
Option C
D
Triangles Q R A and K P L are shown. Triangle Q R A is rotated about point A and then is shifted down and to the left to form triangle K P L.
Option D
19

If bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three options.

Question illustration
A
m∠ABC = 125° and AB ≅ DB
B
ΔACD is isosceles with base AD
C
ΔABD is isosceles with base AD
D
CD = 52 cm
E
AB = 29 cm
20

The proof that ΔACB ≅ ΔECD is shown.Given: AE and DB bisect each other at C.Prove: ΔACB ≅ ΔECD

Question illustration
A
∠BAC ≅ ∠DEC
B
∠ACD ≅ ∠ECB
C
∠ACB ≅ ∠ECD
D
∠BCA ≅ ∠DCA

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