Unit Test — Unit test Answers

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4

Review the graph.

Question illustration
A
quadrant I
B
quadrant II
C
quadrant III
D
quadrant IV
5

A child designs a flag in the shape of a rhombus, as shown in the diagram below. Which expression can be used to determine the side length of the rhombus?

Question illustration
A
StartFraction 10 over cosine 30 degree EndFraction.
Option A
B
StartRoot 800 minus 800 cosine 30 degree EndRoot.
Option B
C
40 cosine 30 degree.
Option C
D
StartRoot 400 minus 40 cosine 30 degree EndRoot.
Option D
6

Let z = and .Which statement describes the geometric construction of the product zw on the complex plane?

Question illustration
A
Stretch z by a factor of 3 and rotate radians counterclockwise.
Option A
B
Stretch z by a factor of 3 and rotate radians counterclockwise.
Option B
C
Stretch z by a factor of 24 and rotate radians counterclockwise.
Option C
D
Stretch z by a factor of 24 and rotate radians counterclockwise.
Option D
8

Let z = and .What is the product of zw?

Question illustration
A
40 (cosine (StartFraction pi Over 16 EndFraction) + I sine (StartFraction pi Over 16 EndFraction) )
Option A
B
76 (cosine (StartFraction pi Over 16 EndFraction) + I sine (StartFraction pi Over 16 EndFraction) )
Option B
C
40 (cosine (StartFraction 3 pi Over 16 EndFraction) + I sine (StartFraction 3 pi Over 16 EndFraction) )
Option C
D
76 (cosine (StartFraction 3 pi Over 16 EndFraction) + I sine (StartFraction 3 pi Over 16 EndFraction) )
Option D
9

The sum of two complex numbers, where the real numbers do not equal zero, results in a sum of 34i. Which statement must be true about the complex numbers?

A
The complex numbers have equal imaginary parts.
B
The complex numbers have equal real parts.
C
The complex numbers have opposite imaginary parts.
D
The complex numbers have opposite real parts.
10

Given w = and , what is w – z expressed in polar form?

Question illustration
A
StartRoot 2 EndRoot (cosine (StartFRaction pi Over 4 EndFraction) + I sine (StartFraction pi Over 4 EndFraction) )
Option A
B
StartRoot 2 EndRoot (cosine (StartFraction 3 pi Over 4 EndFraction) + I sine (StartFraction 3 pi Over 4 EndFraction) )
Option B
C
StartRoot 2 EndRoot (cosine (StartFraction 5 pi Over 4 EndFraction) + I sine (StartFraction 5 pi Over 4 EndFraction) )
Option C
D
StartRoot 2 EndRoot (cosine (StartFraction 7 pi Over 4 EndFraction) + I sine (StartFraction 7 pi Over 4 EndFraction) )
Option D
11

Solve: over the interval .

Question illustration
A
StartFraction pi Over 2 EndFraction
Option A
B
StartFraction 2 pi Over 3 EndFraction
Option B
C
StartFraction 3 pi Over 4 EndFraction
Option C
D
StartFraction 5 pi Over 6 EndFraction
Option D
13

Review the incomplete steps in the derivation of the tangent sum identity.Which action can be taken to the expression in Step 3 to give an expression for Step 4?

Question illustration
A
divide both the numerator and denominator by sin(x)sin(y)
B
divide both the numerator and denominator by sin(x)cos(y)
C
divide both the numerator and denominator by cos(x)sin(y)
D
divide both the numerator and denominator by cos(x)cos(y)
14

Consider w1 = 4 + 2i and w2 = –1 – 3i. Which graph represents the sum w1 + w2?

A
On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. A line goes from (0, 0) to point (3, negative 5).
Option A
B
On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. A line goes from (0, 0) to point (3, negative 1).
Option B
C
On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. A line goes from (0, 0) to point (5, 5).
Option C
D
On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. A line goes from (0, 0) to point (5, 1).
Option D
16

Given z1 = and , what is the value of z1 – z2?

Question illustration
A
cos(0) + isin(0)
B
cos(0) – isin(0)
C
cos() + isin()
Option C
D
cos() – isin()
Option D
19

Let z = 9 – 2i and zw = 25 + 70i.What is w?

A
1 + 8i
B
1 – 8i
C
–1 + 8i
D
–1 – 8i
20

Which equation demonstrates the multiplicative identity property?

A
(negative 3 + 5 i) + 0 = negative 3 + 5 i
Option A
B
(negative 3 + 5 i ) (1) = negative 3 + 5 i
Option B
C
(negative 3 + 5 i) (negative 3 + 5 i) = negative 16 minus 30 i
Option C
D
(negative 3 + 5 i) (3 minus 5 i) = 16 + 30 i
Option D

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