In the diagram, CE=12 units and BE=5 units.

On a coordinate plane, 2 lines are shown. Line H J has points (negative 4, negative 2) and (0, 4). Line F G has points (negative 4, 1) and (0, negative 2).

Lines a and b are parallel lines cut by transversal f.

Given: and Prove: What is the missing reason in the proof?

On a coordinate plane, 2 lines are shown. Line C D has points (negative 2, 4) and (0, negative 4). Line F G has points (negative 4, 0) and (4, 2).

Consider the diagram.

Segment CD is shown on the graph.





On a coordinate plane, line A B goes through (negative 2, 4) and (0, negative 4). Point Z is at (0, 2).

Which diagram shows lines that must be parallel lines cut by a transversal?




In the diagram, the length of segment QV is 15 units.

The midpoint of a segment can be found using the formulas for a directed line segment, x = (x2 – x1) + x1 and y = (y2 – y1) + y1. When using these formulas to find a midpoint, which is true?

Based on this information, which pair of lines, together, could be perpendicular to RS? Select two options.





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On a coordinate plane, line D F goes through points (negative 1, negative 3) and (2, 3). Point G is at (negative 4, negative 4).

The midpoint of is point P at (−6,−2). If point E is at (2,−4), what are the coordinates of point F?

Kevin says that lines p and m will eventually intersect.

On a coordinate plane, 2 lines are shown. Line M N goes through (negative 4, 8) and (negative 4, negative 6). Line K L goes through (negative 8, 2) and (6, 2).

On a coordinate plane, line A B goes through (negative 4, 0) and (2, negative 3). Point C is at (negative 2, 2).

Determine the missing information in the paragraph proof.Given: Line PQ contains points (w, v) and (x, z) and line P'Q' contains points (w + a, v + b) and (x + a, z + b). Lines PQ and P'Q' are parallel.Prove: Parallel lines have the same slope.




On a coordinate plane, a line goes through (negative 12, negative 2) and (0, negative 4). A point is at (0, 6).

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