Using the Distributive Property Answers

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Jaleel and Lisa are simplifying the expression as shown.Jaleel’s MethodLisa’s MethodWhose method is correct and why?

Question illustration
A
Lisa’s method is correct because equals .
Option A
B
Lisa’s method is correct because equals .
Option B
C
Jaleel is correct because equals .
Option C
D
Jaleel is correct because equals .
Option D
4

Tao wants to check that the expression 3(4x – 6) simplifies to 12x – 18. What is the value when 2 is substituted for x into both expressions?

A
The value of each expression is 2.
B
The value of each expression is 6.
C
The value of one expression is 2, and the value of the other expression is 6.
D
The value of one expression is 6, and the value of the other expression is –6.
7

Darren and Quincy wanted to justify that the expression is equivalent to . Their justifications are shown below.Darren’s Method: Substitute 2 into both expressionsQuincy’s Method: Substitute 6 into both expressionsWhich explains who is correct?

Question illustration
A
Only Darren is correct because he substituted x = 2 into the expressions.
B
Only Quincy is correct because he substituted a number that is the same as the denominator of one of the fractions.
C
Both are correct because after substituting the same value into both expressions, the result is the same.
D
Both are correct because they substituted different values into each expression.
8

Which expression is equivalent to 6(x – 4)?

A
–6x + 4
B
6x – 4
C
6x – 24
D
–6x + 24
9

Pablo is simplifying the expression below.He used the steps below to simplify the expression.Which statement is true about the steps that Pablo used to simplify the expression?

Question illustration
A
He combined like terms inside the parentheses, distributed over , and then combined the remaining like terms.
Option A
B
He combined like terms inside the parentheses, distributed over , and then combined the remaining like terms.
Option B
C
He distributed over , distributed 1 over , and then combined like terms.
Option C
D
He distributed over , distributed –1 over , and then combined like terms.
Option D

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