To achieve a speed of 5 m/s, the bottle must be dropped at m.

For a bottle dropped from rest, its speed after falling a height h satisfies v² = 2gh. Solving for the height gives h = v²/(2g) = 5²/(2 × 9.8) ≈ 1.28 m. So the required drop height is 1.28 m, choice A.

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